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3 years ago

Decrease the number 200 by 3/8 of the number.

Mathematics

1 answer:

inysia [295]3 years ago

3 0

Answer:

125

Step-by-step explanation:

Take the 200 and dived into 8s, 25. Multiple that by 3, 75. Subtract 200 by 75, 125

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A box contains 5 plain pencils and 5 pens. A second box contains 3 color pencils and 5 crayon. One item from each box is chosen

Dmitry_Shevchenko [17]

Hello! :)

What is the probability of choosing a pen from the first box? It is 5/10 = 1/2.

What is the probability of selecting a crayon from the second box? It is 5/8.

The probability of picking a pen from the first box and a crayon from the second box is 5/8 x 1/2 = 5/16.

Hope this helped and I hope I answered in time!

Good luck!

~ Destiny ^_^

7 0

3 years ago

Solve for x. −68<8x−4<−36

Lelu [443]

x equals negative 8 and negative 4

3 0

4 years ago

Read 2 more answers

The graph represents the number of cups of flour for the number of cups of sugar ina cake recipe. Which ratio is accurate based

Dmitry_Shevchenko [17]

7.5
I’m not sure
Sorry

7 0

3 years ago

Read 2 more answers

Salsk061 [2.6K]

Answer:

a = 8 ÷ 1/8

Step-by-step explanation:

All I really did was put another variable similar to the x in the original problem, then I changed the numbers to be a bit lower while still keep the original work-- In a short term, I lowered the 9s to 8s.

4 0

3 years ago

National data indicates that 35% of households own a desktop computer. In a random sample of 570 households, 40% owned a deskt

Elan Coil [88]

Answer:

Yes, this provide enough evidence to show a difference in the proportion of households that own a desktop.

Step-by-step explanation:

We are given that National data indicates that 35% of households own a desktop computer.

In a random sample of 570 households, 40% owned a desktop computer.

Let p = population proportion of households who own a desktop computer

SO, Null Hypothesis, $H_0$ : p = 25% {means that 35% of households own a desktop computer}

Alternate Hypothesis, $H_A$ : p $\neq$ 25% {means that % of households who own a desktop computer is different from 35%}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of 570 households who owned a desktop computer = 40%

n = sample of households = 570

So, test statistics = $\frac{0.40-0.35}{{\sqrt{\frac{0.40(1-0.40)}{570} } } } }$

= 2.437

Since, in the question we are not given with the level of significance at which to test out hypothesis so we assume it to be 5%. Now at 5% significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics doesn't lies within the range of critical values of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that % of households who own a desktop computer is different from 35%.

3 0

3 years ago