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Ratling [72]
2 years ago
10

At what height above the ground must a body of mass 20kg be situated in order to have potential energy equal in value to the Kin

etic energy possessed by another body of mass 20kg moving with a velocity of 10m/s? (Take g = 10m/s?)​
Physics
1 answer:
AlladinOne [14]2 years ago
5 0

Answer:


Assuming the height of the first body is h and the speed of the second one is v, just equate the PE of the first with the KE of the second:

mgh = (1/2) mv^2

since they have equal mass, it cancels out and you can solve for h.

Explanation:

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Explanation:

See the attachment for the calculation steps.

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4 years ago
The drawing shows three different resistors in two different circuits. the battery has a voltage of v = 23 v, and the resistors
vesna_86 [32]
Missing picture in the text. I've found it here:
https://www.flickr.com/photos/[email protected]/6791933847/in/photostream

Solution:

Circuit 1)
The three resistors are in series. So the equivalent resistance of the circuit is
R_{eq}=R_1+R_2+R_3 =50.0\Omega+25.0 \Omega+10.0 \Omega=85.0 \Omega
So the current flowing through each resistor is the same, and it is given by Ohm's law:
I= \frac{V}{R_{eq}}= \frac{23 V}{85.0 \Omega}=0.27 A

And the voltage drop across each resistor is given by Ohm's law as well:
V_1 = I R_1 = (0.27 A)(50.0 \Omega)=13.5 V
V_2 = I R_2 = (0.27 A)(25.0 \Omega)=6.8 V
V_3 = I R_3 = (0.27 A)(10.0 \Omega)=2.7 V


Circuit 2)
The three resistors are in parallel, so their equivalent resistance is given by
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}= \frac{1}{50\Omega}+ \frac{1}{25 \Omega}+ \frac{1}{10 \Omega}= \frac{7}{50 \Omega}
R_{eq}= \frac{50}{7} \Omega=7.1 \Omega

The voltage drop across each resistor is the same, and it is equal to the voltage of the battery:
V_1 = V_2 = V_3 = 23 V

while the current across each resistor is given by Ohm's law:
I_1 =  \frac{V}{R_1}= \frac{23 V}{50 \Omega}=0.46 A
I_2 =  \frac{V}{R_2}= \frac{23 V}{25.0 \Omega}=0.92 A
I_3 =  \frac{V}{R_3}= \frac{23 V}{10 \Omega}=2.3 A
5 0
3 years ago
Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the moment of oneâs birth. The on
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Answer:

Explanation:

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Force between baby and Jupiter

F₂ = 6.67x10⁻¹¹ x 1.9x 10²⁷ x 4.1 / ( 6.29 x 10¹¹ )²

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c )

Ratio = 1.01 / 1.31

= .77

4 0
4 years ago
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