You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
pen at both ends and a tube closed at one end. You establish that the fundamental frequency for the new open tube is 463 Hz and for the new closed tube is 852 Hz. Determine the fundamental frequency for the original closed tube. (Use 343 m/s as the speed of sound.)
1 answer:
Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
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Answer:
The magnitude of the force on the wire is 2.68 N.
Explanation:
Given that,
Length of the wire, L = 5 m
Magnetic field, B = 0.37 T
Angle between wire and the magnetic field,
Current in the wire, I = 2.9 A
We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :
So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.
Answer:
Efficiency = 80%
Explanation:
Given the following data;
Work output = 240 N
Work Input = 300 N
To find the mechanical efficiency of a machine;
Substituting into the equation, we have;
Efficiency = 80%
Therefore, the mechanical efficiency of the machine is 80 percent.