You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
pen at both ends and a tube closed at one end. You establish that the fundamental frequency for the new open tube is 463 Hz and for the new closed tube is 852 Hz. Determine the fundamental frequency for the original closed tube. (Use 343 m/s as the speed of sound.)
1 answer:
Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
You might be interested in
Answer:
About 8.3 minutes
Explanation:
Use the formula for velocity as the distance covered by the light divided the time it takes: [/tex]
Use the information about the speed of light in vacuum:
and the information you are given regarding the distance between Sun and Earth:
to solve the first velocity equation for the unknown time "t":
we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes
Answer:
the amplitude of the subsequent oscillations is 0.11 m
the period of the subsequent oscillations is 1.94 s
Explanation:
given Information:
the mass of air-track glider, = 750 g = 0.75 kg
spring constant, k = 13.0 N/m
the mass of glider, = 200 g = 0.2 kg
the speed of glider, = 170 cm/s = 1.7 m/s
the amplitude of the subsequent oscillations is A = 0.11 m
according to mechanical enery equation, we have
where
A is the amplitude and is the final speed.
to find , we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.
= 0, thus
(0.75+0.2) = (0.75)(0)+(0.2)(1.7)
0.95 = 0.34
= 0.36 m/s
Now we can calculate the amplitude
A = 0.11 m
the period of the subsequent oscillations is T = 1.94 s
the equation for period is
T = 2π
T = 2π
T = 1.94 s