You have a length of tubing that is closed at one end. You cut the tubing into two pieces of unequal length, giving you a tube o
pen at both ends and a tube closed at one end. You establish that the fundamental frequency for the new open tube is 463 Hz and for the new closed tube is 852 Hz. Determine the fundamental frequency for the original closed tube. (Use 343 m/s as the speed of sound.)
1 answer:
Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
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The moment of inertial of the wheel,
Explanation:
Given;
8 spokes of uniform diameter
mass of each spoke, =
length of each spoke, = L
mass of outer ring, =
The moment of inertial of the wheel will be calculated as;
where;
is the moment of inertia of each spoke
is the moment of inertia of the rim
Moment of inertia of each spoke
Moment of inertial of the wheel
Answer:
The answer to your question is 636.6 ft
Explanation:
Data
base = 425 ft
angle = 39°
See the picture below
1.- Divide the triangle to get two right triangles.
Now the superior angle will measure 19.5° and the opposite side will measure 212.5 ft
2.- Use the trigonometric function sine to find the hypotenuse
sin 19.5 = 212.5/hyp
solve for hyp
hyp = 212.5 / sin 19.5
Result
hyp = 212.5/ 0.333
hyp = 636.6 ft
