It would be C the moon because the total of all positions (new moon, first quarter, third quarter, full moon, waxing crescent, waning crescent, waxing gibbous, waning gibbous) of the moon would take about 29.6 days on a regular calendar. I hope this helps. :)
The outer planets (Jupiter, Saturn, Uranus, Neptune) are called the "<u>GAS</u> giants".
The rocky planets are called "rocky" because they're made of <u>ROCK</u>.
Does this help guide you to the correct choice ?
Here's another hint: The MOST dense planet in our solar system, the one we call "Earth", is one of the 'rocky planets'.
Given Information:
Initial speed of rock = vi = 30 m/s
escape speed of the asteroid = ve = 24 m/s
Required Information:
final speed of rock = vf = ?
Answer:
vf = 18 m/s
Explanation:
As we know from the conservation of energy
KEf + Uf = KEi + Ui
Where KE is the kinetic energy and U is the potential energy
0 + 0 = ½mve² - GMm/R
When escape speed is used, KEf is zero due to vf being zero. Uf is zero because the object is very far away from mass M, therefore, the equation becomes
GMm/R = ½mve²
m cancels out
GM/R = ½ve²
GM/R = ½(24)²
GM/R = 288
KEf + Uf = KEi + Ui
½mvi² + 0 = ½vf² - GMm/R
m cancels out
½vi² = ½vf² - GM/R
Substitute the values
½(30)² = ½vf² - (288)
½vf² = 450 - 288
vf² = 2(162)
vf = √324
vf = 18 m/s
Therefore, the final speed of the rock is 18 m/s
Answer:
B ) 1.5 m/s
Explanation:
For the apparent frequency reflected by enemy submarine , the Doppler effect formula is
F = F₀ ( V + v) / (V - v)
F anf F₀ are real and apparent frequency , V and v are velocity of sound and velocity of enemy submarine respectively.
ΔF / F₀ = 
Put ΔF = 200; F₀ = 100000 and V = 1482
200 / 100000 = 
v = 1.5 m s⁻¹ .