Answer:
W of the person in moon ≈ 124.70 N
Explanation:
Weight: Weight of a body can be defined as the product of mass and the gravitational acceleration of the body. The S.I unit of weight is Newton (N). It can be expressed mathematically as
W = mg
Where W = weight of the body, m = mass of the body (kg) and a = acceleration of the body (m/s²)
Weight(W) = Mass (m) × Acceleration due to gravity (g)
∴ W = m × g.
If the person is on the moon,
Mass = 76.5 kg.
g (moon) = 16.6% of g ( earth)
But g(earth) = 9.80 m/s².
∴ g (moon) = 9.80 × (16.6/100)
g (moon) = 1.63 m/s², m = 76.5 Kg
∴ Weight of the person in moon = 76.5 × 1.63 =124.695 N
W of the person in moon ≈ 124.70 N
Answer:
a) r = 4.22 10⁷ m, b) v = 3.07 10³ m / s and c) a = 0.224 m / s²
Explanation:
a) For this exercise we will use Newton's second law where acceleration is centripetal and force is gravitational force
F = m a
a = v² / r
F = G m M / r²
G m M / r² = m v² / r
G M / r = v²
The squared velocity is a scalar and this value is constant, so let's use the uniform motion relationships
v = d / t
As the orbit is circular the distance is the length of the circle in 24 h time
d = 2π r
t = 24 h (3600 s / 1 h) = 86400 s
Let's replace
G M / r = (2π r / t)²
G M = 4 π² r³ / t²
r = ∛(G M t² / (4π²)
r = ∛( 6.67 10⁻¹¹ 5.98 10²⁴ 86400² / (4π²)) = ∛( 75.4 10²¹)
r = 4.22 10⁷ m
b) the speed module is
v = √G M / r
v = √(6.67 10⁻¹¹ 5.98 10²⁴/ 4.22 10⁷
v = 3.07 10³ m / s
c) the acceleration is
a = G M / r²
a = 6.67 10⁻¹¹ 5.98 10²⁴ / (4.22 10⁷)²
a = 0.224 m / s²
Answer:
5 feet
Explanation:
First lets imagine that the values are in meters and kg, to make it easier for me.
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The force created by the teacher is 120 × 5 = 600N.
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The force created by the 50 kg student is 50 × 8 = 400N
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The force that needs to be created by the 40 kg student is 600N - 400N = 200N.
To create that force that student needs to sit 200 ÷ 40 = 5m.
So the 40 lbs student is sitting 5 feet from the fulcrum.