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QveST [7]
3 years ago
7

A string of length 3m and total mass of 12g is under a tension of 160N. A transverse harmonic wave with wavelength 25cm and ampl

itude 2cm travels to the right along the string. It is observed that the displacement at x=0 at t=0 is 0.87cm.
a) What is the wave?
b) Wrote the wave function, y(x,t)
c) Find the particle velocity at position x=0 at time t=10s. What is the maximum particle velocity?​
Physics
1 answer:
scoundrel [369]3 years ago
3 0

Answer:

Explanation:wave=wavelength×frequency,

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It is 10.20 m from the ground.

<u>Explanation:</u>

<u>Given:</u>

m = 0.5 kg

PE = 50 J

We know that the Potential energy is calculated by the formula:

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where m is the is mass in kg;  g  is acceleration due to gravity which is 9.8 m/s  and  h  is height in meters.

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Here, if we substitute the values in the formula, we get

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h = \frac {50} {4.9}

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azamat
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I really need help.
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