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Vinil7 [7]
2 years ago
11

I dont know how to d this its cufusing

Mathematics
2 answers:
hoa [83]2 years ago
8 0

Answer:

28

Step-by-step explanation:

a = √8² - 6²

= √64 - 36

= √28

ira [324]2 years ago
3 0
Answer: √28

Solution:
The three squares form a triangle where the hypotenuse is 8 and the right side is divided into 6 and a.

So 8^2 = 6^2 + a^2
(Using the Pythagorean theorem)

64 = 36 + a^2
64 - 36 = a^2
28 = a^2
a = √28
You might be interested in
I need help with these two questions!! I got 72° for Question 7, I don't know I need help with both of them!! PLEASE HELP!! :)
Nat2105 [25]

Answer:

7. 49

8. 10.4

Step-by-step explanation:

7) our hypotenuse is 8, and the side opposite the base of ladder and ground angle is 6, therefore we can use Sin

sin = opposite/hypotenuse

sin(x) = 6/8 = 3/4

sin-1(3/4) = 49

8) using the theorem that alternate exterior angles are congruent

the angle opposite side x is 30

tan = opposite/adjacent

tan(30) = x/18

x = 18tan(30) = 6√(3) = 10.4

you can also use 30-60-90 special right triangles.

the side opposite 30 is x

side opposite 60 is x√(3)

and side opposite 90 is 2x

3 0
3 years ago
Suppose that a random sample of 10 newborns had an average weight of 7.25 pounds and sample standard deviation of 2 pounds. a. T
frosja888 [35]

Answer:

z=\frac{7.25-7.5}{\frac{1.4}{\sqrt{10}}}=-0.565  

p_v =P(Z  

a) If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true average is not significantly less than 7.5.  

b) \chi^2 =\frac{10-1}{1.96} 4 =18.367  

p_v =P(\chi^2 >18.367)=0.0311

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 1.96.

Step-by-step explanation:

Assuming this info: "Suppose birth weights follow a normal distribution with mean 7.5 pounds and standard deviation 1.4 pounds"

1) Data given and notation  

\bar X=7.25 represent the sample mean  

s=1.2 represent the sample standard deviation

\sigma=1.4 represent the population standard deviation

n=10 sample size  

\mu_o =7.5 represent the value that we want to test  

\alpha=0.05,0.01 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 7.5, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7.5  

Alternative hypothesis:\mu < 7.5  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{7.25-7.5}{\frac{1.4}{\sqrt{10}}}=-0.565  

4)P-value  

Since is a left tailed test the p value would be:  

p_v =P(Z  

5) Conclusion  

Part a

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true average is not significantly less than 7.5.  

Part b

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=10 represent the sample size

\alpha=0.01 represent the confidence level  

s^2 =4 represent the sample variance obtained

\sigma^2_0 =1.96 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance increase, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \leq 1.96

Alternative hypothesis: \sigma^2 >1.96

Calculate the statistic  

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{10-1}{1.96} 4 =18.367

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 9. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2 >18.367)=0.0311

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(18.367,9,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 1.96.

4 0
3 years ago
Help help help math math math math
Natasha_Volkova [10]

Answer:

x = 15

Explanation:

First, add both equations on one side, and set it equal to 180° because it's supplementary:

2x + 8 + 8x + 22 = 180

combine like terms:

10x + 30 = 180

subtract 30 on both sides of the equation and you end up with:

10x = 150

divide both sides by 10 and you get:

x = 15

3 0
2 years ago
Read 2 more answers
Find the value of w in the pentagon below if the perimeter is 105 meters.
gavmur [86]

Answer: 9 (with a margin of: 0)

Step-by-step explanation:

Times everything by 5

That gives you 15 + 10w = 105.

Subtract 15 from both sides

Divide by 10 to get w by itself

Then you solve

5 0
3 years ago
What is the mass of 2.5 moles of carbon dioxide?
GarryVolchara [31]

Answer:

110 grams

Step-by-step explanation:

CO2 molecule is made up of Carbon (atomic mass =12) and oxygen (atomic mass=16).

So first finding the mass of 1 molecule of CO2 which is equals to

= mass of 1 carbon atom + masses of 2 oxygen atom, we get

= 12+(16*2)= 12+32= 44 a.m.u.

Now 1 molecule of CO2 has mass 44 amu so mass of 1 mole CO2 will be 44 grams.( 1 a.m.u.=1.6729*10^-33 grams. 1 mole = 6.022*10^23, so 44 a.m.u.=73.6076*10^-33 grams approx. For one mole CO2, 73.6076*10^-33*6.022*10^23 which is approximately equals to 44 grams. )

1 mole CO2= 44grams, so 2.5 moles = 44*2.5= 110 grams

So our answer is 110 grams.

lowkey hope this helped you, good luck whatever you need it for Imaooo

3 0
2 years ago
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