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stellarik [79]
2 years ago
7

Which statements are true?

Mathematics
1 answer:
meriva2 years ago
4 0

Answer:

All rhombuses are rectangles. False

All parallelograms are quadrilaterals. True

All squares are rhombuses. True

All rectangles are squares. False

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Which of the following below could have created this graph
amm1812

Answer:Where is the graph? I'd love to help, but I'd need an image of the graph, please and thank you

5 0
2 years ago
Write the standard equation for the circle with center (6, –8) that passes through (0, 0).(x – 6)2 + (y + 8)2 = 0(x – 6)2 + (y +
Anna [14]
Your equation is:

(x - 6)² + (y + 8)² = 100

When you plug in (0, 0) into this equation, you get:
(0 - 6)² + (0 + 8)² = 100
(- 6)² + 8² = 100
36 + 64 = 100
100 = 100
3 0
3 years ago
146, 74, 38, 20, ? what would the next number be in this sequence?
Anuta_ua [19.1K]
Looking at the numbers, we can see that the differences are 72, 36, and 18. Notice that they are each factors of the next by the same constant 2.

18 * 2 = 36
36 * 2 = 72

There, it means that 18/2 will be subtracted from 20.

20 - 18/2
= 20 - 9
= 11

The next number in the sequence would be 11. Hope this helps!
3 0
3 years ago
0.6 + 15b + 4 = 25.6 all equivelant
Mila [183]

Answer:

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

Step-by-step explanation:

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

0.6 + 15b + 4 = 25.6 all equivelant

3 0
3 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
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