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Ivahew [28]
3 years ago
11

Please help me I don’t understand :(

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0

b=5, commutative property

c=3, associative property

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Nine scores have an average of 8. Scores x and x+1 are added, and these increase the average to 9. Find x
Degger [83]

Answer:

x must be 13

Step-by-step explanation:

Represent the nine scores by a, b, c, d, e, f, g, h, i.

Write the following equation to indicate that the average of these nine scores is 8:

a+b+c+d+e+f+g+h+i

----------------------------- = 8, or <em>a+b+c+d+e+f+g+h+i = 72</em> if we multiply both

               9                      sides of this equation by 9.

Next, we add scores x and x+ 1 to

a+b+c+d+e+f+g+h+i  +  x + x + 1

and divide the result by 11, as there are now 11 scores instead of just 9:

a+b+c+d+e+f+g+h+i  +  x + x + 1

----------------------------------------------

                        11

Earlier, we saw that a+b+c+d+e+f+g+h+i = 72.  We can now replace

a+b+c+d+e+f+g+h+i in the above fraction by 72:

 72 + 2x + 1

------------------- = 9 (as the new average is 9)

         11

Multiplying both sides of this equation by 11 results in:

73 + 2x = 99, or  2x = 26.

Then x must be 13, and x + 1 must be 14.

3 0
3 years ago
What is the bigger number, a googol or a billion?
Doss [256]
A googol is bigger than a billion.
3 0
4 years ago
Read 2 more answers
10 - 2x, when x = 3<br>​
Nesterboy [21]

Answer:

4

Step-by-step explanation:

Plug in 3 as x in the expression:

10 - 2x

10 - 2(3)

10 - 6

= 4

4 0
3 years ago
Read 2 more answers
Equivalent fractions to 1/3
pochemuha
= 2/6 = 3/9 = 12/36 = 24/72 
5 0
3 years ago
What is the difference? startfraction 2 x 5 over x squared minus 3 x endfraction minus startfraction 3 x 5 over x cubed minus 9
weeeeeb [17]

The difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

<h3>How to determine the difference?</h3>

The expression is given as:

\frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x}

Factor the denominators of the expressions:

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x^2 - 9)}

Apply the difference of two squares to x² - 9

\frac{2x^5}{x(x - 3)} - \frac{3x^5}{x(x - 3)(x + 3)}

Take LCM

\frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Hence, the difference of the expression \frac{2x^5}{x^2 - 3x} - \frac{3x^5}{x^3 - 9x} is \frac{2x^5(x + 3) - 3x^5}{x(x - 3)(x + 3)}

Read more about expressions at:

brainly.com/question/723406

#SPJ4

6 0
2 years ago
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