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2 years ago

7

Find the Area of the figure below, composed of a rectangle and a semicircle. The radius of the circle is shown. Round to the nea

rest tenths place

1 answer:

Anarel [89]2 years ago

3 0

Answer:

179.3 square units

Step-by-step explanation:

The area of the figure is the sum of the areas of the parts. That is, the area is the sum of the area of the rectangle, and the area of the semicircle.

__

<h3>Semicircle</h3>

The area of a circle with radius 5 is ...

A = πr²

A = π(5²) = 25π

The area of the semicircle is half that:

semicircle area = (25π)/2 = 12.5π ≈ 39.3 . . . . square units

<h3>Rectangle</h3>

The area of a rectangle with length L and width W is ...

A = LW

The width of this rectangle is the diameter of the circle, twice the radius, or 10 units.

A = (14)(10) = 140 . . . . square units

<h3>Total area</h3>

The sum of the areas of the parts is ...

total area = semicircle area + rectangle area

total area = 39.3 + 140 = 179.3 . . . . square units

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Pls answer (no bit file things) thank you :)

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Answer:

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3 years ago

Sales rise from £400 a week to £504 a week. Calculate the percentage increase

Andrew [12]

Answer:

26%

Step-by-step explanation:

percent change = (new number - old number)/(old number) * 100%

Here, the new number is £504, and the old number is £400.

percent change = (£504 - £400)/(£400) * 100% =

= £104/£400 * 100% = 0.26 * 100% = 26%

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3 years ago

Help……..-What is the rule for the function that is graphed?

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2 years ago

Estimate the sum or difference.

dangina [55]

1) $\frac{4}{6}+\frac{1}{8}=\frac{19}{24}$

2) $\frac{2}{6}+\frac{7}{8}=\frac{29}{24}$

3) $\frac{5}{6}-\frac{3}{8}=\frac{11}{24}$

4) $\frac{4}{6}+\frac{3}{8}=\frac{25}{24}$

5) $\frac{7}{8}-\frac{5}{6}=\frac{1}{24}$

6) $\frac{1}{6}+\frac{7}{8}=\frac{25}{24}$

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

1)

$\frac{4}{6}+\frac{1}{8}=$

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

$4\cdot 4 = 16\\1\cdot 3 = 3$

The expression then becomes:

$\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}$

2)

$\frac{2}{6}+\frac{7}{8}=$

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.

So the new numerators of the two fractions are:

$2\cdot 4 = 8\\7\cdot 3 = 21$

And we get:

$\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}$

3)

$\frac{5}{6}-\frac{3}{8}$

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

$5\cdot 4 = 20\\3\cdot 3 = 9$

And so:

$\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}$

4)

$\frac{4}{6}+\frac{3}{8}=$

Using the same lowest common denominator, 24, the new numerators are:

$4\cdot 4 = 16\\3\cdot 3 = 9$

And so we can rewrite the expression as

$\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}$

5)

$\frac{7}{8}-\frac{5}{6}=$

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

$7\cdot 3 = 21\\5\cdot 4 = 20$

So the expression will be rewritten as:

$\frac{7}{8}-\frac{5}{6}=\frac{21}{24}-\frac{20}{24}=\frac{21-20}{24}=\frac{1}{24}$

6)

$\frac{1}{6}+\frac{7}{8}=$

Here the situation is similar to the first 4 exercises: using 24 as lowest common denominator, the numerators become

$1\cdot 4 = 4\\7\cdot 3 = 21$

So the expression becomes

$\frac{1}{6}+\frac{7}{8}=\frac{4}{24}+\frac{21}{24}=\frac{4+21}{24}=\frac{25}{24}$

Learn more about fractions:

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#LearnwithBrainly

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3 years ago

Here is a line l. Plot 2 points, A and B, which stay in the same place when they are reflected over t. Plot 2 other points, C an

Bad White [126]

Answer:

A and B would be points located along the line itself.

C and D would be points either left or right of the line, but not on the line itself.

Step-by-step explanation:

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2 years ago