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2 years ago

Help me out please !!!!!!!!!!!

Mathematics

1 answer:

Bad White [126]2 years ago

8 0

Answer: A=2, B=5, C=4

Step-by-step explanation:

$\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}$

So A=2, B=5, and C=4.

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Factor the common factor out of -56x4 + 16x2 + 16x

evablogger [386]

Answer:

The common factor is 8x or -8x ( I forgot if the first number needs to positive or not.

Step-by-step explanation:

-8x(7x^3-2x-2)

8x(-7x^3+2x+2)

Hope this is what you are looking for?

5 0

3 years ago

Read 2 more answers

V=M/D

grigory [225]

D=M/V. You just multiply both sides by D to get DV=M, then divide V by both sides.

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2 years ago

Complete the equation of the line through (-9,7) & (-6,-3)

scZoUnD [109]

Answer:

$y=-\frac{10}{3}x-23$

Step-by-step explanation:

we have the points

(-9,7) and (-6,-3)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{-3-7}{-6+9}$

$m=-\frac{10}{3}$

step 2

Find the equation in point slope form

$y-y1=m(x-x1)$

we have

$m=-\frac{10}{3}$

$(x1,y1)=(-6,-3)$

substitute

$y+3=-\frac{10}{3}(x+6)$ ---> equation in point slope form

step 3

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$y+3=-\frac{10}{3}(x+6)$

Isolate the variable y

Distribute right side

$y+3=-\frac{10}{3}x-20$

subtract 3 both sides

$y=-\frac{10}{3}x-20-3$

$y=-\frac{10}{3}x-23$

7 0

2 years ago

Solve each system of equations algebraically y= x-6 y= 2x

lbvjy [14]

Answer: x = -6

Step-by-step explanation: The problem gave us the y value, so we can just substitute it into the equation and solve it.

y = x - 6

y = 2x

2x = x - 6 (substitute the y value into the equation)

1x = -6 (subtract x on each side)

x = -6 (1x is basically saying x so you do not need to divide)

3 0

2 years ago

An animal shelter has 9 puppies. If the puppies are 36% of the total dog and cat population, how many dogs and cats are in the a

Luda [366]

Answer:

Let total number of dog and cat population in animal shelter be x.

As per the statement:

An animal shelter has 9 puppies.

⇒ Total number of puppies = 9

It is also given that if the puppies are 36% of the total dog and cat population.

⇒ $9 = 36\% \text{of}{\text{total number of dogs and Cat}$

$9 = \frac{36}{100} \times x$

By cross multiply we get;

$900 = 36 x$

Divide both sides by 36 we get;

$25 = x$

Therefore, total number of dogs and cat population in animal shelter are 25

5 0

2 years ago