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vodka [1.7K]
2 years ago
10

Help me out please !!!!!!!!!!!

Mathematics
1 answer:
Bad White [126]2 years ago
8 0

Answer: A=2, B=5, C=4

Step-by-step explanation:

\frac{6x^{2}+13x-5}{x^{2}-16} \cdot \frac{x+4}{3x-1}\\\frac{(3x-1)(2x+5)}{(x-4)(x+4)} \cdot \frac{x+4}{3x-1}\\\frac{2x+5}{x-4}

So A=2, B=5, and C=4.

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Step-by-step explanation: hope this helps

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3 years ago
Read 2 more answers
Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

f''(x)=9-\frac{3}{x}

We need to find Third-order derivative of the function f(x).

f''(x)=9-\frac{3}{x}=9-3x^{-1}

We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}

f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}

f'''(x)=-3(-1)x^{-1-1}

f'''(x)=3x^{-2}

f'''(x)=\frac{3}{x^{2}}

Therefore, f'''(x)=\frac{3}{x^{2}}

4 0
4 years ago
1.what is the sum or difference? 3x^8-7x^8<br>A.-4x^16<br>B. -21x^8<br>C. -4x^8<br>D. 10x^-8
Dafna1 [17]
To simplify the given equation, you want to combine like terms. Since both terms have x^8, we can add the coefficients and leave the x^8
3x^8-7x^8 (do 3-7)
=-4x^8 so the answer is C

Hope this helps
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