Solve for x leave your answer in simplest radical form

HELP PLEASE ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!11111

vaieri [72.5K]

Answer:

16(0.5x - 0.75y + 2)

Step-by-step explanation:

16 x 0.5 = 8

16 x -0.75 = -12

16 x 2 = 32

4 0

3 years ago

Read 2 more answers

Jaime en un joven que vive en puyo con su padre. A jaime le gusta cosechar chonta con su padre los sabados en la mañana jaime ha

xenn [34]

Answer:

$\large \boxed{\text{23 s}}$

Step-by-step explanation:

Jaime is at point A and wants to get across the river to Point B.

They must head upstream towards Point C.

1. Calculate the net speed across the river.

∆ABC is a right triangle, so

$\begin{array}{rcl}AB^{2} + BC^{2} & = & AC^{2} \\AB^{2} +10^{2} & = & 12^{2} \\AB^{2}+100& = & 144 \\AB^{2}& = & 44\\AB & = & \sqrt{44}\\& = & 2\sqrt{11}\\& \approx &\textbf{6.633 m/s}\\\end{array}$

2. Calculate the time to cross the river

$\text{Time} = \text{150 m} \times \dfrac{\text{1 s}}{\text{6.633 m}} \approx \textbf{23 s}\\\\\text{It will take $\large \boxed{\textbf{23 s}}$ to cross the river.}$

7 0

3 years ago

X + 54 = 58 what does "x" equal??

MaRussiya [10]

Hey there!

54 + 4 = 58

so x = 4

Hope this helps
Have a great day (:

4 0

3 years ago

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Suppose the weights of tight ends in a football league are normally distributed such that σ2=400. A sample of 11 tight ends was

AlladinOne [14]

Answer:

$217.636-1.96\frac{20}{\sqrt{11}}=205.817$

$217.636+1.96\frac{20}{\sqrt{11}}=229.455$

So on this case the 95% confidence interval would be given by (205.82;229.46)

Step-by-step explanation:

Assuming the following data: Weight 150 169 170 196 200 218 219 262 269 270 271

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma= \sqrt{400}= 20$ represent the population standard deviation

n=11 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean we can use the following formula:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

The mean calculated for this case is $\bar X=217.636$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$