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Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
Answer:
$81.55
Step-by-step explanation:
$15+15%=15x1.15=$17.25
$23+10%=23x1.1=$27.50
$32+15%=32x1.15=$36.80
Total=$81.55
(Time to find a cheaper shop)
