What is the area of this trapezoid?

Solve each triangle for the missing values shown. Show all work necessary. Use exact values

Gelneren [198K]

3)

$Cos 60°= \frac{1}{2} = \frac{Adjacent} {Hypotenuse} = \frac{y} {10} \\\\ 2y=10 \\\\ y=5$

Now, use Pythagoras theorem to find x

$x^2+y^2=10^2 \\\\ \to x^2+5^2=10^2 \\\\ \to x^2+25=100 \\\\ \to x^2 = 100-25 \\\\ \to x^2= 75 \\\\ \to x= \sqrt{75} \\\\ \bf 5 \sqrt{3}$

Similarly,

4)

$Sin 45°= \frac{1}{\sqrt{2}} = \frac{Opposite} {Hypotenuse} =\frac{2 \sqrt{2}} {a} \\\\ a= 2 \sqrt{2} \times \sqrt{2} \\\\ a=4$

Now, use Pythagoras theorem to find b

$b^2+(2 \sqrt{2}) ^2=a^2 \\\\ \to b^2+8=4^2 \\\\ \to b^2=16-8 \\\\ \to b^2 = 8\\\\ \to b= \sqrt{8} \\\\ \bf b=2 \sqrt{2}$

You can solve all of them in a similar way.

: )

7 0

3 years ago

I need help I’m struggling

andrew-mc [135]

All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)

The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes

I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.

Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place

The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.

I hope this makes sense and helps you out a bit... have a good day

8 0

3 years ago

What is the next term in the sequence

Nesterboy [21]

Answer:

-5/2

Step-by-step explanation:

The next term will be,

→ -2/4

→ (-2-3)/(4÷2)

→ -5/2

Hence, the solution is -5/2.

8 0

2 years ago

Read 2 more answers

Please answer asap! will mark brainliest :)

tekilochka [14]

Answer:

your answer is 6460

<u><em>Happy Valentine's Day!!<3</em></u>

Step-by-step explanation:

19 * 17 * 20 =6460

7 0

3 years ago

The amount of money in a savings account after t years is represented by the function f(t)=500(1.015)^t. What does the value 500

MaRussiya [10]

Answer:

Find out the what does the value 500 represent in this situation .

To prove

As given

The amount of money in a savings account after t years is represented by the function.

$f(t)=500(1.015)^{t}$

Exponential function for amount is given by .

$Amount = a (1 + r)^{t}$

Wher a is the initial value, r is the rate in decimal form and t is the time.

Compare the functions

$f(t)=500(1.015)^{t}$

and

$Amount = a (1 + r)^{t}$

Thus a = 500

Therefor $500 is the initial value .

4 0

3 years ago