Step-by-step explanation:
The x's will simply cancel each other out and you will be left with a 6
hope it makes sense
:)
A. Let s be the smallest integer
B. We must add 2 to get the next greater integer
C. Second integer is s+2
D. s+(s+2)=118
2•s+2=118
2s+2-2=118-2
2s=116
2s/2=116/2
s=58
If the smallest even integer is 58 the consecutive integer is 58+2=60
Verify
58+60=118 ✔️
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
B . Approaches -4
I’m pretty sure it’s -4
Answer:
- 7, - 3, 1, 5
Step-by-step explanation:
Using the recursive rule and a₁ = - 7, then
a₂ = a₁ + 4 = - 7 + 4 = - 3
a₃ = a₂ + 4 = - 3 + 4 = 1
a₄ = a₃ + 4 = 1 + 4 = 5
The first four terms are - 7, - 3, 1, 5
