Answer:
The required mass is 22.04 g
Explanation:
We know,
Atomic mass of Co= 58g.
Now,
1 mole Co = 58 g
∴ 0.38 mole Co= (58 X 0.38) g
= 22.04 g
So, the required mass is 22.04 g
<span>It must generate hydroxide ions in the water
hope i helped</span>
Answer:
1.0190 x 10⁻⁵ mol
Explanation:
We know the titration required 10.19 mL of 0.001000 M KIO₃, from this information we can calculate the number of moles KIO₃ reacted and from there the number of moles of ascorbic acid since it is a monoprotic acid ( 1 equivalent of ascorbic acid to one equivalent KIO₃).
Molarity = mol/V
V KIO₃ = 10.19 mL = 10.19 mL x 1 L/1000 mL = 0.01019 L
⇒ mol KIO₃ = V x M = 0.01019 L x 0.0010 mol / L = 1.0190 x 10⁻⁵ mol KIO₃
# mol ascorbic acid = # mol KIO₃ = 1.0190 x 10⁻⁵ mol
A. Nonmetallic
B. Nonmetallic
C. Metallic
D. Nonmetallic
E. Metallic