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3 years ago

In a nuclear reaction, the parent element is always radioactive.

1 answer:

7 0

Hydrogen to be more precise protium which is an isotope of hydrogen containing one proton and one electron. It is considered to be very stable which explains it's abundance everywhere. However under extreme conditions like in the sun, it undergoes nuclear fusion to form helium. So in conclusion, under normal circumstances Protium is considered to be very stable however under extreme circumstances it is radioactive. Does that answer your question?

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6.9 moles of oxygen gas in a fixed volume of 1.33 liters. One of the valves opened and there remains only 1.24 moles oxygen gas.

Romashka [77]

Answer:

The new volume of the gas remains the same. That is new volume of gas is 1.33 litres

Explanation:

This is because gases do not have a definite shape. They therefore take the shape of their containing vessels and hence their volumes are determined by the volume of the container.

For the question above even if some of the gas escapes, as long as there is gas present in the container, its volume remains the same, that is occupies the same space in the container

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2 years ago

1. Land-dwelling creatures depend on the the water cycle to ___________ fresh water from its salt solution in the Earth's oceans

Novosadov [1.4K]

1 is evaporate and 2 is precipitate

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3 years ago

Read 2 more answers

A gas of unknown identity diffuses at a rate of 155 mL/s in a diffusion apparatus in which carbon dioxide diffuses at the rate o

Ostrovityanka [42]

Answer:

19.07 g mol^-1

Explanation:

The computation of the molecular mass of the unknown gas is shown below:

As we know that

$\frac{Diffusion\ rate\ of unknown\ gas }{CO_{2}\ diffusion\ rate} = \frac{\sqrt{CO_{2\ molar\ mass}} }{\sqrt{Unknown\ gas\ molercular\ mass } }$

where,

Diffusion rate of unknown gas = 155 mL/s

CO_2 diffusion rate = 102 mL/s

CO_2 molar mass = 44 g mol^-1

Unknown gas molercualr mass = M_unknown

Now placing these values to the above formula

$\frac{155mL/s}{102mL/s} = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ 1.519 = \frac{\sqrt{44 g mol^{-1}} }{\sqrt{M_{unknown}} } \\\\ {\sqrt{M_{unknown}} } = \frac{\sqrt{44 g mol^{-1}}}{1.519} \\\\ {\sqrt{M_{unknown}} } = \frac{44 g mol^{-1}}{(1.519)^{2}}$

After solving this, the molecular mass of the unknown gas is

= 19.07 g mol^-1

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3 years ago

Does a reptile play the same role as a bird in the WNV???<br> PLZ HURRY PLZ

Slav-nsk [51]

The birds could have more diseases and could pass it to other reptiles

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3 years ago

Sonbull [250]

Answer: option B. Poles

Explanation:

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3 years ago