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3 years ago

In which material are the particles arranged in a regular geometric pattern?

Chemistry

1 answer:

Illusion [34]3 years ago

6 0

I think only solids arrange in a regular geometric pattern, so i2

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Arrange these molecules in order of decreasing mass: C6H14 , NO2 , Fe2O3 , and CaCO

babunello [35]

The following is the arrangement of the given molecules in decreasing order of mass: $\text{ Fe2O3} > \text{C6H14} > \text{CaCO} > \text{NO2}$

Solution:

First inorder to arrange the elements in descending order of their mass we have to calculate the molecular mass of each element. The calculation is as follows:

Mass of C6H14:

$C\rightarrow6\times12.01 = 72.06$

$H\rightarrow14\times1.008 = 14.112$

Mass of C6H14 is 86.172

Mass of NO2:

$N\rightarrow1\times14.0067 = 14.0067$

$O\rightarrow2\times15.9994 = 31.9988$

Mass of NO2 is 46.0055

Mass of Fe2O3:

$Fe\rightarrow2\times55.845 = 111.69$

$O\rightarrow3\times15.9994 = 47.9982$

Mass of Fe2O3 is 159.6882

Mass of CaCO:

$Ca\rightarrow1\times40.078 = 40.078$

$C\rightarrow1\times12.01 = 12.01$

$O\rightarrow1\times15.9994 = 15.9994$

Mass of CaCO will be 68.0874

So, the order will be $159.6882>86.172>68.0874>46.0055$ which is $\text{ Fe2O3} > \text{C6H14} > \text{CaCO} > \text{NO2}$

6 0

3 years ago

How many atoms in total are there in 7.35 mol of magnesium oxide (MgO) molecules?

andreev551 [17]

Answer:

4.42 x 10^24

Explanation:

3 0

3 years ago

Lead (Pb) is used to make a number of different alloys. What is the mass of lead present in an alloy containing 0.15 mol of lead

Vesna [10]

Lead is 207.2 g/mol.
$0.15 mol (\frac{207.2g}{mol}) = 31.08 g Pb$

3 0

3 years ago

Why might it be useful to determine the elements that a planet or moon is made up of?

GuDViN [60]

to see if its copatible with our environment or to see if there is any unkown element, otherwise i dont know

if wrong very sorry

5 0

3 years ago

How many atoms are in 0.075 mol of titanium?

Annette [7]

The mass of titanium is = 47,867 g/1mol

Applying the rule of avrogado

1mol _______ 6,023 × 10^(23) at

0,075mol ___ x

X . 1mol = 0,075mol . 6,023 . 10^(23)at

X = 0,075 . 6,023 . 10^(23) at

X = 4,51 . 10^(22) atoms

Hope this helps

7 0

3 years ago

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