Explain how to separate a mixture of sand and pebbles.

Chemistry

1 answer:

Dimas [21]3 years ago

7 0

You could use a strainer, and let the sand fall out while pebbles stay in.

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Types of catalyst..... <br>Plsz.....

Fantom [35]

Answer:

Explanation:

(1) Homogeneous, (2) Heterogeneous (solid), (3) Heterogenized homogeneous catalyst and (4) Biocatalysts

4 0

3 years ago

If I add 475mL of water to 75.0mL of a 0.315M NaOH solution, what will the molarity of the diluted solution be?

pantera1 [17]

Answer is: <span>the molarity of the diluted solution 0,043 M.
</span>V(NaOH) = 75 mL ÷ 1000 mL/L = 0,075 L.
c(NaOH) = 0,315 M = 0,315 mol/L.
n(NaOH) = c(NaOH) · V(NaOH).
n(NaOH) = 0,075 L · 0,315 mol/L.
n(NaOH) = 0,023625 mol.
V(solution) = 0,475 L + 0,75 L.
c(solution) = 0,023625 mol ÷ 0,550 L.
c(solution) = 0,043 mol/L.

5 0

4 years ago

Magnesium chloride is an important coagulant used in the preparation of tofu from soy milk. Its solubility in water at 200C is 5

Gennadij [26K]

Answer:

(a) Homogeneous. 4.7 g of MgCl₂.

(b) 9.1 g

Explanation:

(a)

At 200°C, we can dissolve 54.6g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

$38.2gWater.\frac{54.6gMgCl_{2}}{100gWater} =20.9g$

Since we can dissolve up to 20.9 g of MgCl₂ and we added only 16.2 g, the mixture is homogeneous and we could add 20.9 g -16.2 g = 4.7 g of solute to make it saturated.

(b)

At 800°C, we can dissolve 66.1 g of MgCl₂ in 100 g of water. The mass that we could dissolve in 38.2 g of water is:

$38.2gWater.\frac{66.1gMgCl_{2}}{100gWater} =25.3g$