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SVEN [57.7K]
2 years ago
10

13 The enrollment at Eldridge Middle School has been tracked for two years. The enrollment was 1,648 students in 2015. The table

shows the change in enrollment from the previous year.
Mathematics
1 answer:
telo118 [61]2 years ago
8 0

Play this game to review Mathematics. The
able shows school enrollment for Bayview
Middle School. Find the rate of change fro...
lissing: Eldridge tracked 7648
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Use f(x) = 2 x and f-'(x) = 2x to solve the problems.
Westkost [7]

Answer:

f(2) = 1

f(1) = \frac{1}{2}

f^{-1}(2)=4

Step-by-step explanation:

Consider the provided functions.

f(x) = \frac{1}{2}x

f^{-1}(x)=2x

Find f(2) as shown.

Substitute x=2 in f(x) = \frac{1}{2}x

f(2) = \frac{1}{2}\times2

f(2) = 1

Find f(1) as shown.

Substitute x=1 in f(x) = \frac{1}{2}x

f(1) = \frac{1}{2}

Find f'(2) as shown.

Substitute x=2 in f^{-1}(x)=2x

f^{-1}(2)=2(2)

f^{-1}(2)=4

8 0
3 years ago
Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec
o-na [289]

Answer:

(a) The probability of the event (<em>X</em> > 84) is 0.007.

(b) The probability of the event (<em>X</em> < 64) is 0.483.

Step-by-step explanation:

The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 64.

The probability mass function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...

(a)

Compute the probability of the event (<em>X</em> > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

                =1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007

Thus, the probability of the event (<em>X</em> > 84) is 0.007.

(b)

Compute the probability of the event (<em>X</em> < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

                =\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483

Thus, the probability of the event (<em>X</em> < 64) is 0.483.

5 0
3 years ago
You went to the mall with $52.50. You bought three shirts that each cost x
yanalaym [24]
52.50-3x=Remainder
Explanation:
52.50 starting amount
3x (3 shirts) (1 shirt=x)
52.50-3 shirts=remainder
7 0
4 years ago
(1 point) If xyz = 23, find the value of<br> (8z) (x/4) (10y).
Dimas [21]

Answer:

460

Step-by-step explanation:

(8z)(x/4)(10y)=20xyz=20(23)=460

3 0
2 years ago
Add me on snap gamerdylan19 insta is reaper_shot and tiki's Tok is death_shot55
3241004551 [841]

Answer:

ok xd

Step-by-step explanation:

5 0
3 years ago
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