Answer:
Find an nth-degree polynomial function.
Step-by-step explanation:
n= 3;
- 2 and 6 + 2 i are zeros;
f(-1)= 53
Answer:
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
Step-by-step explanation:
Given that,
A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.
From Pythagorean Theorem,
(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+
Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.
∴y²= x²+10²

Differentiating with respect to t


Since the car driving towards the intersection at 13 m/s.
so,

Now



= -12 m/s
Negative sign denotes the distance between the car and the person decrease.
Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.
This just wants the derivative which you can solve for.
You can do this using a negative expononet or using ...the rational rule forget its name*.... you shoudl get 9000/(t+12)^2
*Quotient rule
Correction:
I think the question should be like that find the approximate value of
P(-0.78 < z < 1.16)?
Now,
the symbol Ф represent the cumulative density.
first find the
Ф(1.16) from the above given table which is equal to 0.8770.
Now,
find the Ф(-0.78) .
in our table we are given the value of Ф(0.78)=0.7823
so as the curve is symmetrical Ф(-0.78)=1-0.7823=0.2177
P(-0.78 < z < 1.16) = Ф(1.16)-Ф(-0.78)
= 0.8770-0.2177
= 0.6593
The angles are complementary meaning they =90 degrees.
So take (x-20) and x, and write this equation,
x-20+x=90
2x-20=90
move the 20 over
2x-20=90
+20 +20
2x=110
x=55.
You can check it by plugging it back in,
(55-20)=35
and
x=55
35+55=90.
Thus, you know your answer is correct.