Show that (2,1) is a solution of the system of equations

Mathematics

1 answer:

almond37 [142]2 years ago

3 0

Answer: (2,1)

Step-by-step explanation:

You might be interested in

What is the 30°-60°-right triangle theorem?

kondaur [170]

<span>the 30°-60°-right triangle theorem states that the
</span>In a right triangle, the hypotenuse is twice as long as a leg if and only if the measure of the
<span>angle opposite that leg is 30°
so the option C is correct from above all
</span>see the figure
hope it helps

4 0

3 years ago

How do you right a number in its prime factorization?

Whitepunk [10]

Please use "write" here, not "right." "write" is "right" here, if you get my drift.
"right" is wrong in this context. ;)

Example: Most of us would see immediately that 5 is a prime factor of 50.

Write 50 as 5 * 10.

10 is not prime; it can be factored into 5 and 2.

Thus, 50 written as the product of its prime factors is 5 * 5 * 2 (answer)

7 0

3 years ago

If a determinant of a 2 x 2 matrix is 0, what can you conclude about the inverse of the matrix?

icang [17]

Any singular matrix (a matrix with zero determinant) has no inverse.

3 0

3 years ago

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

zaharov [31]

Answer with Step-by-step explanation:

Given

$f(x)=\frac{1-cos(2x)}{1-cos(x)}\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\\\\(\because cos(2x)=cos^2x-sin^2x)\\\\\lim_{x \rightarrow 0}f(x)=\lim_{x\rightarrow 0}(\frac{1-cos^2x}{1-cos(x)}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}(\frac{(1-cosx)(1+cosx)}{1-cosx}+\frac{sin^2x}{1-cosx})\\\\=\lim_{x\rightarrow 0}((1+cosx)+\frac{sin^2x}{1-cosx})\\\\\therefore \lim_{x \rightarrow 0}f(x)=1$

6 0

3 years ago

Write the algebraic expression for 5 groups of x

Nadusha1986 [10]

Answer:

Step-by-step explanation:

8 0

3 years ago