5x^4
Step-by-step explanation:
simply we take 5x^4 bec. it can be divided by 40 and 135
<span>The number of x-intercepts that appear on the graph of the function
</span>f(x)=(x-6)^2(x+2)^2 is two (2): x=6 (multiplicity 2) and x=-2 (multiplicity 2)
Solution
x-intercepts:
f(x)=0→(x-6)^2 (x+2)^2 =0
Using that: If a . b =0→a=0 or b=0; with a=(x-6)^2 and b=(x+2)^2
(x-6)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x-6)^2] = sqrt(0)→x-6=0
Adding 6 both sides of the equation:
x-6+6=0+6→x=6 Multiplicity 2
(x+2)^2=0
Solving for x. Square root both sides of the equation:
sqrt[ (x+2)^2] = sqrt(0)→x+2=0
Subtracting 2 both sides of the equation:
x+2-2=0-2→x=-2 Multiplicity 2
Answer:
c. 0.3974
Step-by-step explanation:
Given;
number of white balls, W = 17
number of red balls, R = 18
Total number of balls, T = 35
The number of ways the event will occur is given by
= P(2 whites) and P(2 reds)
= P(2whites) x P(2 reds)
= 17C2 x 18C2
= 136 x 153
= 20,808
The total number of possible outcome
= 35C4
= 52,360
The probability = 20,808 / 52,360
= 0.3974
The correct option is "C"
Answer:
1620°
Step-by-step explanation:
The figure is an 11-sided polygon and is called hendecagon
The interior angle sum:
180( n-2) n=11
=180(11-2)
=180(9)
=1620°
I hope this help you
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.
Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
