Balance the equation, show steps:Ag (s) + H2S (g) + O2 (g) ⟶ Ag2S (s) + H2O (l)

Chemistry

1 answer:

ehidna [41]3 years ago

5 0

4Ag + 2H2S + O2 -> 2Ag2S + 2H20 i’m pretty sure that’s correct

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If copper carbonate system is heated for too short a time, what will you notice for mass percent of copper be too large or too s

sammy [17]

Answer:

The mass percent of copper as element is the same.

Explanation:

First of all we need the reaction that is presented below:

$CuCO_{3 (s)} +Heat$ → $CuO_{(s)} + CO_{2 (g)}$

The mass percent of copper (Cu) as element is the same because of during the reaction the element only transform its nature from copper carbonate ( $CuCO_{3 (s)}$ ) to copper oxide ( $CuO_{(s)}$ ), the latter is a solid and will remain in the system.

On the other hand, you will note that the global percentage mass will be small because of the reaction produce ( $CO_{2 (g)}$ ) that is a gas and this one will escape for the system.