X+y=8
2x^2-y=-5
elimination method means you link the 2 equations together to make one
these two already have y in the perfect form where you can cancel it out +y and -y so no need to perform any other action to a certain equation.. all you need to do is add them now
2x^2+x=3
Answer:
I think it is 6/7
Step-by-step explanation:
I am really bad at explaining but I'm not completely sure
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
4p(x-4)-5
That is my answer I hope I’m right have a merry Christmas
Answer:
Is there a x somewhere or is that litteraly how the equation is?
If so, -7 multiplied by 2 is -14,
-1 times -7 is 7,
add it together and you get
-7=28,
you could add 7 to both sides or subtract 28 from both sides and you'll get either 0=35 or -35=0
which would make the solution false since both sides are not the same
