What is pulverization?__Easy steps to cry XD

Mathematics

2 answers:

ICE Princess25 [194]3 years ago

5 0

Pulverization is defined as the separation of particles from each other rather than the breaking up of individual particles.

<h3>What is pulverization?</h3>

Pulverization is defined as the separation of particles from each other rather than the breaking up of individual particles.

It is applied in several fields, for instance, pulverization in waste management is simply the process of grinding collected solid waste into powder using the grinding machine thereby changing its volume and physical characteristic.

Learn more on pulverization here: brainly.com/question/21400963

german3 years ago

3 0

The separation of particles from each other rather than the breaking up of individual particles.

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Need help ASAP (You dont have to show work, just answer it)

anyanavicka [17]

Answer:

$50.40 is the answer

Step-by-step explanation:

12% of 45 is 5.40 so if we add $5.40 and $45 we get $50.40

hope this helps ^-^ have a wonderful day

4 0

3 years ago

Read 2 more answers

Select the correct answer.

DedPeter [7]

Answer: The correct option is (D) (4, -6).

Step-by-step explanation: Given that the areas of the triangles ADC and DCB are in the ratio 3 : 4.

We are to find the co-ordinates of point C.

From the diagram, we note that

the co-ordinates of point A and B are A(1, -9) and B(8,-2).

So, the length of the line segment AB, calculated by distance formula, is

$AB=\sqrt{(1-8)^2+(-9+2)^2}=\sqrt{49+49}=7\sqrt2.$

Now, area of ΔADC is

$A_{ABC}=\dfrac{1}{2}\times AC\times CD,$

and area of ΔDCB is

$A_{DCE}=\dfrac{1}{2}\times BC\times CD.$

According to the given information, we have

$A_{ADC}:A_{DCB}=3:4\\\\\\\Rightarrow \dfrac{A_{ADC}}{A_{DCE}}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{\frac{1}{2}\times AC\times CD}{\frac{1}{2}\times BC\times CD}=\dfrac{3}{4}\\\\\\\Rightarrow \dfrac{AC}{BC}=3:4.$

So, the point C divides the line segment AB internally in the ratio 3 : 4.

We know that

if a point divides a line segment with end-points (a, b) and (c, d) internally in the ration m : n, then its co-ordinates are

$\left(\dfrac{mc+na}{m+n},\dfrac{md+nb}{m+n}\right).$

Since point C divides the line segment AB with end-points A(1, -9) and B(8, -2) internally, so the co-ordinates of point C will be

$\left(\dfrac{3\times 8+4\times 1}{3+4},\dfrac{3\times (-2)+4\times (-9)}{3+4}\right)\\\\\\=\left(\dfrac{28}{7},\dfrac{-42}{7}\right)\\\\\\=(4, -6).$