Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.
I hope it helps you get it right
Answer:
3+x<5x+2
Step-by-step explanation:
the sum of the number 3+xis less than so 3+x<5×x+2
<em>so</em><em> </em><em>final</em><em> </em><em>ans</em><em> </em><em>is</em><em> </em><em><u>3</u></em><em><u>+</u></em><em><u>x</u></em><em><u><</u></em><em><u>5</u></em><em><u>x</u></em><em><u>+</u></em><em><u>2</u></em>
Answer:
About 316,955 people
Step-by-step explanation:
The population of this city can be modeled with the formula 
, where P represents the current population, I represents the initial population, and t represents the amount of time in years since the start of the model. Plugging in 145,201 for I and (2037-2021)=16 for t, we get:
Answer:
x= 12
Step-by-step explanation:
2(x-7) = 10
Distribute the 2. 2x-14 = 10
Add the 14 onto both sides to cancel it out on the original side and following the rules- the same must be done to the other side. 2x-14 (+14) = 10+14 -----> 2x = 24
Divide both sides by 2 to get the X alone. 2x/2 = 24/2 ---------> x= 12
