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MrMuchimi
2 years ago
14

Find g. Write your answer as an integer or as a decimal rounded to the nearest tenth.

Mathematics
1 answer:
Soloha48 [4]2 years ago
6 0

Step-by-step explanation:

\frac{EG}{  \sin(/EFG)  } =   \frac{EF}{ \sin(/EFG) }  \\  \frac{7}{ \sin(36°) }  =  \frac{g}{ \sin(121°) }  \\ g = 10.208

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What's the depth of 5cm
nordsb [41]

Answer:

what?

Step-by-step explanation:

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2 years ago
In the figure shown, m∠ABD=8x−28 and m∠DBC=4x+10.
prohojiy [21]

In geometry, the segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

7 0
1 year ago
iTunes and Amazon each have plans for downloading music. iTunes charges $5.00 to join and $0.75 per song. Amazon has no fee to j
aleksandrvk [35]

Answer:

20 songs.

Step-by-step explanation:

we are given that,  iTunes charges $5.00 to join and $0.75 per song.

Amazon has no fee to join and charges $1.00 per song.

Let x songs would you have to download (same number of downloads for each company) so that the prices are the same.

Then we can write

5+0.75x=1x\\\text{take like terms together by adding -0.75x on both the sides}\\5+0.75x-0.75x=1x-0.75x\\5=0.25x\\\text{Divide both the sides by 0.25}\\x=20

7 0
3 years ago
Greatest common factor 84 and 100
harina [27]

Answer:

4

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
(X^4)-(45x^2)+324 what are the zeroes? And how many turning points?
dmitriy555 [2]

Zeroes:

We must solve

x^4-45x^2+324=0

To do so, we define the auxiliary variable t=x^2. The equation becomes

t^2-45t+324=0

The quadratic formula yields the solutions

t=9,\quad t=36

Substituting back t=x^2 gives

x^2=9 \iff x=\pm 3,\quad x^2=36 \iff x=\pm 6

So, the zeroes are -6, -3, 3, 6.

Turning points:

Turning points are points where a function stops being increasing to become decreasing, or vice versa. Since functions are increasing when their first derivative is positive and decreasing when it's negative, turning points are points where the first derivative is zero.

We have

f(x)=x^4-45x^2+324 \implies f'(x)=4x^3-90x

If we set the derivative to be zero, we have

4x^3-90x=0 \iff x(4x^2-90)=0

So, the derivative is zero if x=0 or

4x^2=90 \iff 2x^2=45 \iff x^2=\dfrac{45}{2}\iff x=\pm\sqrt{\dfrac{45}{2}}

6 0
3 years ago
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