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3 years ago

Find the volume of a cylindrical container,whose height is 21cm and diameter is 14cm?

Mathematics

2 answers:

Lena [83]3 years ago

4 0

Answer:

1029 $\pi$

Step-by-step explanation:

Volume= $\pi$ x $(radius)^{2}$ x height = $\pi$ x $7^{2}$ x 21 = 1029 $\pi$

I hope it helps you!

Sati [7]3 years ago

3 0

Answer:

923.75cm³

<h3>steps</h3>

volume of a cylinder πr²h

r=d/2. 14/2 =7cm

volume= 3.142×7²×21

=3,322.12cm³

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9341/2 scientific notation

Darya [45]

Answer: 9.34 x 10^3
Hope this helps

5 0

4 years ago

Which equation is equivalent to 2(3x-5)=5-2(1-x)

aniked [119]

Answer:

6(x-10)=5-2(1-x)

Step-by-step explanation:

I divided by 3 the parenthesis, and multiplied by 3 the first number, which makes an equivalent equation.

7 0

3 years ago

jay beats terry at table tennis 3 out of 5 games. what is the experimental probability that terry will win their next game

lozanna [386]

Answer:

The experimental probability that terry will win their next game is $\frac{2}{5}$

Step-by-step explanation:

While theoretical probability is the ratio of the number of favourable outcomes to the total number of outcomes, the experimental probability is the ratio of number of times the event is occurring to the total number of trials of the experiment.

Out of 5 games jay wins 3

Now the experimental probability that terry will win their next game

= 1 - Probability of Jay winning the game----------------------(1)

Probability of Jay winning the game = $\frac{\text{number of occurrences of the event}}{\text{total number of trials made}}$

=> $\frac{3}{5}$ ----------------------------------------------------(2)

Substituting (2) in (1)

=> 1 - $\frac{3}{5}$

=> $\frac{5-3}{5}$

=> $\frac{2}{5}$

6 0

3 years ago

Plzzzzz help will give brainlyist

nikdorinn [45]

Answer:

Step-by-step explanation:

You do 12 x 3 which is 36.

you then do 1/3 x 3 which is 1.

36-1 is 35.

you then do 4x3 which is 12.

you then do 12-5 which is 7.

you then do 35÷7=5

this is why it is 5.

6 0

3 years ago

A survey on British Social Attitudes asked respondents if they had ever boycotted goods for ethical reasons (Statesman, January

Blababa [14]

Answer:

a) 27.89% probability that two have ever boycotted goods for ethical reasons

b) 41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) 41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) The expected number is 2.3 and the standard deviation is 1.33.

Step-by-step explanation:

We use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

23% of the respondents have boycotted goods for ethical reasons.

This means that $p = 0.23$

a) In a sample of six British citizens, what is the probability that two have ever boycotted goods for ethical reasons?

This is P(X = 2) when n = 6. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{6,2}.(0.23)^{2}.(0.77)^{4} = 0.2789$

27.89% probability that two have ever boycotted goods for ethical reasons

b) In a sample of six British citizens, what is the probability that at least two respondents have boycotted goods for ethical reasons?

Either less than two have, or at least two. The sum of the probabilities of these events is decimal 1. So

$P(X < 2) + P(X \geq 2) = 1$

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = 0) = C_{6,0}.(0.23)^{0}.(0.77)^{6} = 0.2084$

$P(X = 1) = C_{6,1}.(0.23)^{1}.(0.77)^{5} = 0.3735$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.2084 + 0.3735 = 0.5819$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.5819 = 0.4181$

41.81% probability that at least two respondents have boycotted goods for ethical reasons

c) In a sample of ten British citizens, what is the probability that between 3 and 6 have boycotted goods for ethical reasons?

Now n = 10.

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

$P(X = 3) = C_{10,3}.(0.23)^{3}.(0.77)^{7} = 0.2343$

$P(X = 4) = C_{10,4}.(0.23)^{4}.(0.77)^{6} = 0.1225$

$P(X = 5) = C_{10,5}.(0.23)^{5}.(0.77)^{5} = 0.0439$

$P(X = 6) = C_{10,6}.(0.23)^{6}.(0.77)^{4} = 0.0109$

$P(3 \leq X \leq 6) = P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.2343 + 0.1225 + 0.0439 + 0.0109 = 0.4116$

41.16% probability that between 3 and 6 have boycotted goods for ethical reasons

d) In a sample of ten British citizens, what is the expected number of people that have boycotted goods for ethical reasons? Also find the standard deviation.

$E(X) = np = 10*0.23 = 2.3$

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.23*0.77} = 1.33$

The expected number is 2.3 and the standard deviation is 1.33.

5 0

3 years ago