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QveST [7]
2 years ago
8

An electronics company packages its product in cube-shaped boxes. These boxes are placed into a larger box that measures 3 ft lo

ng, 114 ft wide, and 2 ft tall. The edge length of each cube-shaped box is 14 ft. How many cube-shaped boxes can fit into the container? 240 boxes 480 boxes 720 boxes 960 boxes.
Mathematics
1 answer:
gladu [14]2 years ago
8 0

The number of boxes fitted in the larger container is found out by the volume of both boxes.

The number of boxes fitted into the larger container is 480.

<h3>What is the volume?</h3>

The volume can be defined as the space occupied by an object in three dimensions.

Given that the edge of the cube box is 1/4 ft. The dimensions of the larger box are 3 ft long, 1 1/4 ft wide, and 2 ft.

The volume of the cube box is calculated as given below.

V_s = s^3

Where Vs is the volume of the cube box and s is the edge of the cube box.

V_s = \dfrac {1}{4}^3

V_s = 0.015625\;\rm ft^3

The volume of the larger box is calculated as given below.

<em />V = l \times w\times h

Where V is the volume, l is length, w is width and h is the height of the larger box.

V = 3 \times \dfrac {5}{4} \times 2

V = 7.5\;\rm ft^3

The number of cube boxes fitted into the larger box is calculated as given below.

No. \; of \;boxes = \dfrac {V}{V_s}

No. \; of \;boxes = \dfrac {7.5}{0.015625}

No. \; of \;boxes = 480

Hence we can conclude the number of boxes fitted into the larger container is 480.

To know more about the volume, follow the link given below.

brainly.com/question/1578538.

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Put the steps in order. *
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The answer is 3 , 1 , 2 .

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I will give an example.

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What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?
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Step 1

<u>Find the slope of the given line</u>

Let

A(-3,2)\ B(2,-1)

slope mAB is equal to

mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}

Step 2

<u>Find the slope of the line that is perpendicular to the given line</u>

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}

Step 3

<u>Find the equation of the line with mCD and the point (3,0)</u>

we know that

the equation of the line in the form point-slope is equal to

y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5

Multiply by 3 both sides

3y=5x-15

5x-3y=15

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation 5x-3y=15

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