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2 years ago

12

The most common battery cable terminal is a ________ that provides a large surface contact area with the ability to tighten the

terminal onto the battery post using a nut and bolt.

1 answer:

Dmitriy789 [7]2 years ago

3 0

It’s a cone design bozo

You might be interested in

Circumference of a circle given the radius or diameter? explain why or why not

djyliett [7]

Circumference of a circle can be calculated if the radius or the diameter is given.

<u>Explanation</u>:

Circumference or the perimeter of a circle can be calculated if the radius or the diameter of the circle is given.
This is calculated by the formula - 2 * pi * r (if radius is given) and pi * d (if diameter is given) where pi = 3.14, r = radius and d = diameter
This calculation is based on the fact that the circumference is three and a little more times that of the radius. Since the diameter is double that of the radius, when the diameter is given formula becomes pi*d.

3 0

3 years ago

A diverging lens has a focal length of magnitude 22.8 cm. (a) Locate the images for each of the following object distances. 45.6

Nostrana [21]

(a) -15.2 cm

We can solve the problem by using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

f = -22.8 cm is the focal length of the lens (negative because it is a diverging lens)

p = 45.6 cm is the distance of the object from the lens

q is the distance of the image from the lens

Solving the equation for q, we find the position of the image:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{45.6 cm}=-0.066 cm^{-1}$

$q=\frac{1}{-0.066 cm^{-1}}=-15.2 cm$

and the negative sign means that the image is virtual.

(b) -11.4 cm

In this case, the distance of the object from the lens is

p = 22.8 cm

Substituting into the lens equation, we can find the new image distance, q:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{22.8 cm}=-\frac{2}{22.8 cm}$

$q=\frac{-22.8 cm}{2}=-11.4 cm$

and the negative sign means that the image is virtual.

(c) -7.6 cm

In this case, the distance of the object from the lens is

p = 11.4 cm

Substituting into the lens equation, we can find the new image distance, q:

$\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{-22.8 cm}-\frac{1}{11.4 cm}=-0.132 cm^{-1}$

$q=\frac{1}{0.132 cm^{-1}}=-7.6 cm$

and again, the negative sign means that the image is virtual.

3 0

3 years ago

7 questions, lots of points, please answer as many as possible.

maw [93]

4. gravitational
5.all
6.sound
7.all
8.chemical
9.electrical.
10.sound

6 0

4 years ago

An Indy 500 race car's velocity increases from 4.0 m/s to +36

Soloha48 [4]

Answer:

The average acceleration is $8\ m/s^2$

Explanation:

<u>Uniform Acceleration </u>

When an object varies its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

$v_f=v_o+a.t$

Where:

vf = Final speed

vo = Initial speed

a = Constant acceleration

t = Elapsed time

The acceleration can be calculated by solving for a:

$\displaystyle a=\frac{v_f-v_o}{t}$

The Indy 500 race car increases its speed from vo=4 m/s to vf=36 m/s in t=4 s. Thus, the average acceleration is:

$\displaystyle a=\frac{36-4}{4}=8\ m/s^2$

The average acceleration is $8\ m/s^2$

3 0

3 years ago

Just need some help trying to figure out some of these practice questions. Please and thank you!!!

dangina [55]

Answer:

10. 3

11. 1

12. 3

Explanation:

10. Everybody has different things that they find stressful. Stressful situations are associated heightened anxiety, fear, and worry. Different situations and life events can trigger stress. Public speaking is a good example of a stressful situation, as it often makes people nervous and uncomfortable. The other options are not usually associated with stress

11. After division of a cell containing 46 chromosomes (diploid), the genetic content is divided equally between 2 cells, producing two daughter cells with 23 chromosomes (haploid). Sex cells are the only cells in the body that are haploid. At fertilisation, 2 haploid cells come together to form a diploid cell.

12. After the whales died, the bones settled in the ocean sediments that moved with the changing land. The bones would not be preserved after animal activity or floating in the ocean. Options 4 and 5 do not explain how the whale bones ended up out of the water.

3 0

3 years ago