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2 years ago

12

The most common battery cable terminal is a ________ that provides a large surface contact area with the ability to tighten the

terminal onto the battery post using a nut and bolt.

1 answer:

Dmitriy789 [7]2 years ago

3 0

It’s a cone design bozo

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As altitude increases in the troposphere and stratosphere, the air temperature does what?

natima [27]

Answer:

1

Explanation:

3 0

3 years ago

Consider the sections of two circuits illustrated above. Select True or False for all statements. After connecting c and d to a

Basile [38]

Answer:

Follows are the solution to the given question:

Explanation:

In this question the missing file of the circuit is not be which is defined in attached file please find it.

In Option 1, this statement is true because the current is on $R_3 \ and \ R_4$ , that is the same.

In option 2, this statement is false because $Rcd=R_3+R_4$ therefore it implies that Rcd is always larger then $R_3$ .

In option 3, this statement is true because the voltage of $R_1 \ and \ R_2$ is always equal.

In option 4, this statement is true because $Rab= \frac{1}{(\frac{1}{R1}+\frac{1}{R2})}=\frac{R1R2}{(R1+R2)}. \frac{R2}{(R1+R2)}$ is always smaller then 1 therefore, $R_1 \times (\frac{R2}{(R1+R2)})$ is always equal to R1.

5 0

3 years ago

This. please help me.

kramer

The transfer of heat from the Sun is in the form of thermal radiation (also called infrared radiation)
The transfer of heat at the person’s feet is by thermal conduction. During the day the sand will be hot so if you step on it with bare feet there will be conduction of heat to the feet.

3 0

3 years ago

2. Willingness to take turns is one way we can express our attitudes through

leva [86]

B because willingness shows confidence in your answer

3 0

3 years ago

You have a stopped pipe of adjustable length close to a taut 62.0-cm, 7.25-g wire under a tension of 3910 N . You want to adjust

Ber [7]

Answer:

L = 6 cm

Explanation:

Second overtone of the wire is same as third harmonic

so its frequency is given as

$f = \frac{3}{2L}\sqrt{\frac{T}{\mu}}$

here we know that

$\mu = \frac{M}{L}$

$\mu = \frac{7.25 \times 10^{-3}}{0.62}$

$\mu = 0.0117 kg/m$

now we have

$f = \frac{3}{2\times 0.62}\sqrt{\frac{3910}{0.0117}}$

$f = 1398.6 Hz$

Now fundamental frequency of sound in a pipe is given as

$f = \frac{v}{4L}$

$1398.6 = \frac{340}{4L}$

$L = 0.06 m$

$L = 6 cm$

7 0

3 years ago