The best way in handling in this situation is that in order for the astronaut to be able to get back to the shuttle is that he or she should take an object from his or her tool belt and to be thrown out away from the shuttle. This will allow her to weight lightly and safely return to the shuttle and would be easier for his or her to do so.
Answer:
The work done by this force can be found via the following formula

Explanation:
Alternatively, the work done by the object is equal to the elastic potantial energy done by the spring.

Answer:
7.78x10^-8T
Explanation:
The Pointing Vector S is
S = (1/μ0) E × B
at any instant, where S, E, and B are vectors. Since E and B are always perpendicular in an EM wave,
S = (1/μ0) E B
where S, E and B are magnitudes. The average value of the Pointing Vector is
<S> = [1/(2 μ0)] E0 B0
where E0 and B0 are amplitudes. (This can be derived by finding the rms value of a sinusoidal wave over an integer number of wavelengths.)
Also at any instant,
E = c B
where E and B are magnitudes, so it must also be true at the instant of peak values
E0 = c B0
Substituting for E0,
<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²
Solve for B0.
Bo = √ (0.724x2x4πx10^-7/ 3 x10^8)
= 7.79 x10 ^-8 T
Answer:

Explanation:
We need to apply conservation of momentum and energy to solve this problem.
<u>Conservation of momentum</u>

(1)
- m(c) is the mass of stick clay
- m(w) is the mass of the wooden block
- v(ic) is the initial velocity of clay
- V is the final velocity of the system clay plus wood.
<u>Conservation of total energy</u>
The change in kinetic energy is equal to the change in internal energy, in our case it would be the energy loss due to the friction force. Let's recall the definition of work, it is the dot product between force and displacement, Therefore:



We can find V from this equation:

Now, let's put V into the equation (1) and find v(ic)

I hope it helps you!
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False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.