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3 years ago

Probably the deadliest aspect of a thunderstorm is _____. rain thunder lightning hail

2 answers:

max2010maxim [7]3 years ago

8 0

The answer to the given question is lightning.
Lightning is most probably the deadliest aspect of a thunderstorm. It is a sudden electrostatic discharge during an electrical storm. It happens when there is an electrostatic discharge between electrically charged regions of a cloud, which is referred as the intra-cloud lightning or IC, between that cloud and another cloud or the CC lightning, or between a cloud and the ground (CG lightning).

kipiarov [429]3 years ago

3 0

Probably the deadliest aspect of a thunderstorm is lightning .

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A marble resting near the edge of .90 m high table is given an initial horizontal speed of 1.24 m/s. What will be it’s horizonta

Maru [420]

Answer:

0.53 m

Explanation:

First of all, we have to consider the vertical motion of the ball, in order to find the time it takes for the marble to reach the ground. The initial height is $h=0.90 m$ , the initial vertical velocity is zero, while the acceleration is $g=-9.81 m/s^2$ , so the vertical position at time t is given by

$y(t)=h-\frac{1}{2}gt^2$

By demanding y(t)=0, we find the time t at which the ball reaches the ground:

$0=h-\frac{1}{2}gt^2$

$t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(0.9 m)}{9.81 m/s^2}}=0.43 s$

Now we can find the horizontal range of the marble: we know the initial horizontal speed (v=1.24 m/s), we know the total time of the motion (t=0.43 s), and since the horizontal speed is constant, the total distance traveled on the horizontal direction is

$x=vt=(1.24 m/s)(0.43 s)=0.53 m$

8 0

3 years ago

In 1993 Ileana Salvador of Italy walked 3.0km in under 12min. Suppose that during her walk Salvador is observed to steadily incr

padilas [110]

The distance covered is 115 m

Explanation:

The motion of Ileana is a uniformly accelerated motion (constant acceleration), therefore we can use the following suvat equation:

$s=(\frac{u+v}{2})t$

where

s is the distance covered

u is the initiaal velocity

v is the final velocity

t is the time elapsed

In this problem, we have:

u = 4.20 m/s

v = 5.00 m/s

t = 25.0 s

Therefore, we can re-arrange the equation to find the distance covered:

$s=(\frac{4.20+5.00}{2})(25.0)=115 m$

Learn more about accelerated motion:

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#LearnwithBrainly

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3 years ago

What is a element that tends to be shiny, easy shaped, and a good conductor of heat?

ozzi

The answer to your question is Metal

8 0

3 years ago

A jogger ran her first 100 meters in 50 seconds then ran another 150 meters in 50 seconds. What is the jogger’s average speed: W

Stella [2.4K]

Answer:

Explanation:

Learn vocabulary, terms, and more with flashcards, games, and other study tools. ... A jogger sprints 100 m in 13 seconds. What is her average speed? 7.7 m/s ... Kathryn swam 5 complete laps of a 50 m pool. ... stands still for 4 seconds, then continues to walk for 8 meters moving away from the starting point in 6 seconds.

6 0

3 years ago

In an emergency an airplane needs to land on a short runway at Albany County Airport. The plane comes in for a landing with a sp

zvonat [6]

Answer:

t = 13.43 s

Explanation:

In order to find the minimum time required by the plane to stop, we will use the first equation of motion. The first equation of motion is written as follows:

Vf = Vi + at

where,

Vf = Final Velocity of the Plane = 0 m/s (Since, the plane finally stops)

Vi = Initial Velocity of the Plane = 95 m/s

a = deceleration of the plane = - 7.07 m/s²

t = minimum time interval needed to stop the plane = ?

Therefore,

0 m/s = 95 m/s + (- 7.07 m/s²)t

t = (95 m/s)/(7.07 m/s²)

t = 13.43 s

6 0

3 years ago