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Svetllana [295]
3 years ago
7

Probably the deadliest aspect of a thunderstorm is _____. rain thunder lightning hail

Physics
2 answers:
max2010maxim [7]3 years ago
8 0
The answer to the given question is lightning.
Lightning is most probably the deadliest aspect of a thunderstorm.  It is <span> a sudden </span>electrostatic discharge<span> during an </span>electrical storm. It happens <span> when there is an electrostatic discharge between </span>electrically charged<span> regions of a </span>cloud, which is referred as the i<span>ntra-cloud lightning or IC, between that cloud and another cloud or the CC lightning, or between a cloud and the ground (CG lightning).</span>
kipiarov [429]3 years ago
3 0

Probably the deadliest aspect of a thunderstorm is <u>  lightning  </u> .

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Which change would cause the largest increase in a mountain climber’s gravitational potential energy?
3241004551 [841]
<span>carrying twice the weight and climbing twice as high</span>
5 0
3 years ago
Read 2 more answers
According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s
Mademuasel [1]

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

now we have

\frac{dL}{dt}= 0

now we also know that

Area = \frac{1}{2}r^2d\theta

so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

4 0
3 years ago
A car traveling on a straight road at 15.0 meters per second accelerates uniformly to a speed of 21.0 meters per second in 12.0
oksano4ka [1.4K]
<h2>Option 3,  216 m is the correct answer.</h2>

Explanation:

We have initial velocity, u = 15 m/s

Time, t = 12 seconds

Final velocity, v = 21 m/s

We have equation of motion v = u + at

Substituting

                     21 = 15 + a x 12

                       a = 0.5 m/s²

Now we have equation of motion v² = u² + 2as

                           21² = 15² + 2 x 0.5 x s

                            s = 216 m

       Displacement = 216 m

Option 3,  216 m is the correct answer.

8 0
4 years ago
Figure 3 shows a bicycle of mass 15 kg resting in a vertical position, with the front and back
Vinil7 [7]

Explanation:

There are three forces on the bicycle:

Reaction force Rp pushing up at P,

Reaction force Rq pushing up at Q,

Weight force mg pulling down at O.

There are four equations you can write: sum of the forces in the y direction, sum of the moments at P, sum of the moments at Q, and sum of the moments at O.

Sum of the forces in the y direction:

Rp + Rq − (15)(9.8) = 0

Rp + Rq − 147 = 0

Sum of the moments at P:

(15)(9.8)(0.30) − Rq(1) = 0

44.1 − Rq = 0

Sum of the moments at Q:

Rp(1) − (15)(9.8)(0.70) = 0

Rp − 102.9 = 0

Sum of the moments at O:

Rp(0.30) − Rq(0.70) = 0

0.3 Rp − 0.7 Rq = 0

Any combination of these equations will work.

3 0
3 years ago
The thrust from a car is 2000 N. The air resistance and friction together total 680 N. What happens to the speed of the car?
zheka24 [161]
The car will speed up because if the air resistance and friction forces are reacting in the direction opposite to the Applied force, The Net force will still be in the direction of the car's motion and since F=ma a will cause your velocity to increase
6 0
4 years ago
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