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Svetllana [295]
3 years ago
7

Probably the deadliest aspect of a thunderstorm is _____. rain thunder lightning hail

Physics
2 answers:
max2010maxim [7]3 years ago
8 0
The answer to the given question is lightning.
Lightning is most probably the deadliest aspect of a thunderstorm.  It is <span> a sudden </span>electrostatic discharge<span> during an </span>electrical storm. It happens <span> when there is an electrostatic discharge between </span>electrically charged<span> regions of a </span>cloud, which is referred as the i<span>ntra-cloud lightning or IC, between that cloud and another cloud or the CC lightning, or between a cloud and the ground (CG lightning).</span>
kipiarov [429]3 years ago
3 0

Probably the deadliest aspect of a thunderstorm is <u>  lightning  </u> .

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Suppose that a solid ball, a solid disk, and a hoop all have the same mass and the same radius. Each object is set rolling witho
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Answer:

Hoop will reach the maximum height

Explanation:

let the mass and radius of solid ball, solid disk and hoop be m and r  (all have same radius and mass)

They all  are rolled with similar initial speed v

by the law of conservation of energy we can write

K_{trans}+K_{rot}= P

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[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{ball}\omega^2= mgh_{ball}

putting I_{ball}=\frac{2}{5}mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

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[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{disk}\omega^2= mgh_{disk}

putting I_{ball}=\frac{1}{2}mr^2 and \omega=\frac{v}{r} in the above equation and solving we get

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for hoop

[tex]\frac{1}{2}mv^2+\frac{1}{2}I_{hoop}\omega^2= mgh_{hoop}

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clearly from the above calculation we can say that the Hoop will reach the maximum height

5 0
3 years ago
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