Conclusion about distance, average speed, and time
1 answer:
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Answer:
17.1130952381 s
No
Explanation:
t = Time taken
u = Initial velocity = 115 m/s
v = Final velocity = 0
s = Displacement
a = Acceleration = -6.72 m/s² (negative as it is decelerating)
From the equations of motion
The minimum time required to stop is 17.1130952381 s
The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.