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2 years ago

14

A 2N and 6N force pull on an object to the right and a 4N force pulls to the left a 0.5kg object. What is the net force on the o

bject?

1 answer:

Angelina_Jolie [31]2 years ago

3 0

Explanation:

F net = 2+6-4 ( 2 and 6 N are in same direction so they get added, 4N in opposite direction so it will be subtracted)

F net=4 N

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What is Newton's Second Law?

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Answer:

An object's acceleration depends on its mass and on the net force acting on it.

Explanation:

Newton's second law states that the acceleration of an object is directly related to the net force and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

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3 years ago

Consider a cloudless day on which the sun shines down across the United States. If 2073 kJ of energy reaches a square meter ( m

Mnenie [13.5K]

The total amount of energy per hour is $2.039\cdot 10^{16} kJ$

Explanation:

In this problem we are told that the amount of energy reaching a square meter in the United States per hour is

$E_1 = 2073 kJ$

The total surface area of the United States is

$A=9.834\cdot 10^6 km^2$

And converting into squared metres,

$A=9.834\cdot 10^6 \cdot 10^6 = 9.834\cdot 10^{12} m^2$

Therefore, the total energy reaching the entire United States per hour is given by:

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3 years ago

Determine the number of ways to throw two die and get the number 11, as well as the probability of getting 11.

Ivenika [448]

Answer:

1/18

Explanation:

The number of ways in which two die can be thrown is the sample space of the experiment

(1,1), (1,2) (1,3), (1,4) (1,5) (1,6)

(2,1), (2,2) (2,3), (2,4) (2,5) (2,6)

(3,1), (3,2) (3,3), (3,4) (3,5) (3,6)

(4,1), (4,2) (4,3), (4,4) (4,5) (4,6)

(5,1), (5,2) (5,3), (5,4) (5,5) (5,6)

(6,1), (6,2) (6,3), (6,4) (6,5) (6,6)

From here it can be seen that there are only two cases where the sum on the two die is 11 i.e., (6,5) and (5,6)

$\text{Probability of getting 11}=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\\\Rightarrow \text{Probability of getting 11}=\frac{2}{36}\\\Rightarrow \text{Probability of getting 11}=\frac{1}{18}=0.056$

∴ Probability of getting 11 is<u> 1/18</u>

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3 years ago