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3 years ago

Which of the following shows the correct order of the body systems involved in this response?

Physics

1 answer:

dem82 [27]3 years ago

7 0

B. Circulatory, respiratory, nervous

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A student wants to draw a model of an atom. Which statement describes how to find the number of neutrons to include in the model

katrin2010 [14]

Answer:

The number of electrons is not important (eliminate B and C)

The mass number is equal to or greater than the atomic number

(this leaves only D)

Mass number is the total mass of the nucleus (neutrons + protons)

Subtracting the atomic number from the mass number gives:

Mass number - Atomic number = number of neutrons

3 0

2 years ago

A constant force pushes on a brick, as shown below. A constant force pushes on three bricks as shown below. 师

JulijaS [17]

Answer:

5 UNDER 5

Explanation:

7 0

2 years ago

Which term names the part of a sound wave by which frequency or pitch is measured?

Oksanka [162]

Answer:

Hertz

Explanation:

How long is a sound wave? Sound frequency (pitch) is measured in Hertz. 1 Hz is one cycle per second.

7 0

1 year ago

if you drive your car at an average speed of 105km/h, how far (in km) will you go in 3hours 30minutes ?

irinina [24]

Hi ;-)

1 hour ⇒ 105 km

0,5 hour (30 minutes) ⇒ 105 km : 2 = 52,5 km

3 hours 30 minutes ⇒ 3 · 105 km + 52,5 km =

= 315 km + 52,5 km = <u>367,5 km</u>

5 0

2 years ago

Find the resultant of the following forces: 3.0N east, 4.0N west, and 5.0N in a direction north 60° west.

zzz [600]

Answer:

5.5 N at 50.8° north of west.

Explanation:

To find the resultant of these forces, we have to resolve each force along the x- and y-direction, then find the components of the resultant force, and then calculate the resultant force.

The three forces are:

$F_1=3.0 N$ (east)

$F_2=4.0 N$ (west)

$F_3=5.0 N$ (at 60° north of west)

Taking east as positive x-direction and north as positive y-direction, the components of the forces along the 2 directions are:

$F_{1x}=3.0 N\\F_{1y}=0$

$F_{2x}=-4.0 N\\F_{2y}=0$

$F_{3x}=-(5.0)(cos 60^{\circ})=-2.5 N\\F_{3y}=(5.0)(sin 60^{\circ})=4.3 N$

Threfore, the components of the resultant force are:

$F_x=F_{1x}+F_{2x}+F_{3x}=3.0+(-4.0)+(-2.5)=-3.5 N\\F_y=F_{1y}+F_{2y}+F_{3y}=0+0+4.3=4.3 N$

Therefore, the magnitude of the resultant force is

$F=\sqrt{F_x^2+F_y^2}=\sqrt{(-3.5)^2+(4.3)^2}=5.5 N$

And the direction is:

$\theta=tan^{-1}(\frac{F_y}{|F_x|})=tan^{-1}(\frac{4.3}{3.5})=50.8^{\circ}$

And since the x-component is negative, it means that this angle is measured as north of west.

7 0

2 years ago