If Point C and D are equidistant from point A, it means that AC and AD are of the same length. AC = AD
AC = AD (S) (<span>Points C and D are equidistant from point A)
</span>AE = AE (S) (The two triangle shared the same side)
∠CAE = ∠EAD (A) (This angle is between the two sides that we just proved to be equal)
By SAS,
ΔEAD ≡ ΔEAC
Answer:The given function is .Minimum or maximum value:At the extremum (maximum or minimum) value, the function will have zero slope. So, differentiate the given function once and equate it to zero to get the extremum point.dy/dx=0Now, check whether the point x=0 is corresponding to the maximum value or minimum value by differentiating the function twice,As for all value of x, so x=0 is the point corresponding to minima.Put x=0 in the given function to get the minimum value.Domain and range:The function defined for all the values of the independent variable, x.So, the domain is .The range of the function is the possible value of y.The minimum value, for x=0, is y=7.The maximum value, as .Hence the range of the function is .The value of x for which the function is increasing and decreasing:If the slope of the function is negative than the function is decreasing, soThen, from equation (i), the value of x for which dy/dx<0,18x<0Hence, the function is decreasing for .While if the slope of the function is positive than the function is increasing, soThen, from equation (i), the value of x for which dy/dx<0,18x>0Hence, the function is increasing for
Step-by-step explanation:hope this helps
Answer: Ann = 67 Josh = 60 Claire = 30
Step-by-step explanation: You get the equation 5x+7 = 157. You get the equation because for example, Claire = x then josh = 2x and Ann = 2x + 7. You do all the math and boom! You get the answer :)
Answer:
how to help u the picture is black
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ANSWER:</h2>
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<u><em>9400</em></u>
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Step-by-step explanation:</h2><h3><u><em>
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Take 94 x 100 and get = 9400</em></u></h3><h2><u><em /></u></h2>
<u><em>Thank you for asking this great question need any other help please let me know by commenting below I'd be glad to help.</em></u>
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<u><em>Your brainly friend ( lauralit1 )</em></u>
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