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rjkz [21]
3 years ago
14

A 5,000 Kg monster truck is traveling at 11 m/s. when it sees an obstacle it is going to crush during the Monster truck rally, i

t speeds up to 18 m/s. how much has the kinetic energy of the truck increased during this time?
A). 302,500
B). 507,500
C). 810,000
D). 120,600
Physics
1 answer:
avanturin [10]3 years ago
5 0

The change in the kinetic energy of the monster truck during the time is 507500 J and the right option is B). 507500

<h3>What is kinetic energy?</h3>

Kinetic energy is the energy of a body due to its motion.

To calculate the increase in the kinetic energy of the monster truck, we use the formula below.

Formula:

  • ΔK.E = m(v²-u²)/2............. Equation 1

Where:

  • ΔK.E = Increase in kinetic energy of the monster truck
  • m = mass of the monster truck
  • v = final velocity of the monster truck
  • u = initial velocity of the monster truck.

From the question,

Given:

  • m = 5000 kg
  • v = 18 m/s
  • u = 11 m/s.

Substitute these values into equation 1

  • ΔK.E = 5000(18²-11²)/2
  • ΔK.E = 2500(324-121)
  • ΔK.E = 2500(203
  • ΔK.E = 507500 J

Hence, The increase in the kinetic energy of the monster truck during the time is 507500 J and the right option is B). 507500.
Learn more about kinetic energy here: brainly.com/question/25959744

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Explanation:

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3 years ago
An ideal spring has spring constant ks (to distinguish it from the electrostatic constant k) and equilibrium length l. Then, you
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Answer:

q = square root (4KsL³/k)

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See the attachment below for full solution.

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Answer:

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Explanation:

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where

F is the force exerted on the web

k is the spring constant

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In this problem, we have:

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x=4.0 mm=0.004 m

So if we solve eq.(1) for k, we find the spring constant:

k=\frac{F}{x}=\frac{1.47\cdot 10^{-4} N}{0.004 m}=0.037 N/m

3 0
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