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Agata [3.3K]
4 years ago
10

An ideal spring has spring constant ks (to distinguish it from the electrostatic constant k) and equilibrium length l. Then, you

glue two identical negative point charges to the ends of the spring and observe that the equilibrium length doubles. Determine the amount of charge on each end of the spring

Physics
1 answer:
nexus9112 [7]4 years ago
5 0

Answer:

q = square root (4KsL³/k)

The force of extension of the spring is equal to the force of repulsion between the two like charges. Two like charges(positive or negative) would always repel each other and two unlike charges would always attract each other. This electric force between the charges is what is responsible for the stretching of the spring. The electric force causes the spring to increase in length from L to 2L. Equating these forces, that is the electric force between the charges and the elastic force of the spring and rearranging the variables gives the expression to obtain q.

Explanation:

See the attachment below for full solution.

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Two stars in a faraway part of the Milky Way are orbiting each other as a binary star system. By
natita [175]

Answer: M_{total}= 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of <em>Kepler's Third Law</em>, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

a^{3}=(M_{1}+M_{2})P^{2}

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

M_{1}+M_{2} is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

P=\frac{594}{365}

P = 1.63 years

Calculating total mass:

a^{3}=(M_{total})P^{2}

M_{total}=\frac{a^{3}}{P^{2}}

M_{total}=\frac{1.7^{3}}{1.63^{2}}

M_{total}= 1.85

<u>The total mass of the two-object system is 1.85 mass units.</u>

3 0
3 years ago
The "Garbage Project" at the University of Arizona reports that the amount of paper discarded by households per week is normally
Lorico [155]

Answer:

54%

Explanation:

We are given that

S.D=4.2 lb

Mean=\mu=9.4 lb

We have to find the percentage of household throw out at least 9 lb of paper  a week.

Normal distribution formula :

P(X\geq a)=P(z\geq \frac{a-\mu}{\sigma})

We have a=9

P(X\geq 9)=P(z\geq \frac{9-9.4}{4.2})=P(z\geq -0.1)

P(X\geq 9)=1-P(z

P(X\geq 9)=1-0.4602=0.5398\times 100=54%

Hence, the  percentage of household throw out at least of paper a week=54%

7 0
3 years ago
En una báscula hidráulica colocamos una persona de 75 kg sobre un émbolo y un camión de 7200 kg sobre una plataforma de 5 m de l
TEA [102]

...........................

4 0
4 years ago
Como se representa un intervalo de tiempo
atroni [7]
Come se in so mi tiempo si
6 0
2 years ago
An ammeter is connected in series with a resistor of unknown resistance R and a DC power supply of known emf e. A student uses t
rosijanka [135]

Answer:

B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Explanation:

Here,power has been calculated using current I and total EMF \ε . So,P=EMF*current= ε I will represent total power dissipated in resistor and ammeter.

Now, this total power P has been dissipated in both resistor and ammeter. So, power dissipated in resistor must be less than P as some power is also dissipated in ammeter because it has non-zero resistance.

So, the answer is B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Note that option A,C and E are ruled out as they state power dissipated by resistor is greater than or equal to P which is false.

Also,option D is ruled out as ammeter is connected in series.

8 0
4 years ago
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