Yes, Avery, Mc Leod and Mc Carty do thought that genes may be involved in the transformation of non virulent rough Strains of <em>Diplococcus pneumoniae</em> to harmful smooth strained bacteria
<h3><u>Explanation:</u></h3>
Avery was a Canadian medical researcher who along with other two well known scientists of the contemporary time went for an experiment where he took two strains of bacteria Diplococcus pneumoniae - one is rough and nonvirulent and another is smooth and virulent. For a control run, he injected both the bacteria in separate mice and the expected result was there. Now as he injected heat killed smooth bacteria, the mice survived. But as he injected heat killed smooth bacteria with rough bacteria, although there was no organism which can kill the mice the mice died. And autopsy revealed the presence of live smooth bacteria in the lungs.
Thus they suspected something have gone from the dead smooth bacteria into the non virulent rough bacteria which lead to transformation of the rough bacteria to smooth ones. Thus, the experiment was carried on, which suspected role of genes in this transformation.
Answer:
The reason for the offspring to present these genotypes is that during the formation of the gametes, the alleles separate and are inherited independently, therefore they can generate several different phenotypic combinations.
Explanation:
In order for an offspring to present very different phenotypes, as shown in the question above, it is necessary that the two red griffins with blue eyes that were crossed are heterozygous. Thus it will be possible for the offspring to present a wide variety of phenotype, according to Mendel's second law.
Mendel's second law is called the Law of segregation. This law explains that the alleles (which determine the characteristics of individuals) are separated in the formation of gametes and inherited by the offspring of a cross independently, and can generate different combinations of phenotypes, when the parents of a cross are heterozygous.
The answer is B) Amoeba
hope this helps
Answer: Option D) 1:4
Explanation:
Recall that the sum of all nitrogenous bases in the DNA nucleotide is equal to 100%. And specific base pairings of Adenine to Thymine (A=T), and Cytosine to Guanine (C=G) must be equal.
So, the percentage of Adenine equal thymine, and that of cytosine equals guanine.
Now, A + T + C + G = 100%
So, if adenine makes up 10% of the DNA nucleotides, then thymine is also 10%.
Then, 10% + 10% + C + G = 100%
20% + C + G = 100%
C + G = 100% - 20% = 80%
Thus, divide 80% by 2 to obtain the individual percentage of cytosine and guanine. Each will take 40%
Ratio Adenine to Guanine is 10% to 40%
or 1:4 in simplest form
