Answer:
(0, 7/12)
Step-by-step explanation:
to find the y intercept we equate x to 0.
hence,
f(0) = 7/12
the coordinate is (0, 7/12)
To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
W will be at the points (-6,-2) after 180 degrees counterclockwise rotation
This question have 2 different answer depending on what law he is stating in this problem
Solution 1
=> 204 / 32 = 6.38 times did 32 goes to 204.
Solution 2
=> 204 - 32 = 172
=> 172 / 32 = 5.38
=> 5.38 * 100% - 538%
Answer:
Step-by-step explanation:
When Riko left his house, Yuto was 5.25 miles along the path.
Average speed of Riko = 0.35 miles per minute
Average speed of Yuto = 0.25 miles per minute
First we will calculate the time in which Riko will catch Yuto on the track.
Relative velocity of Riko as compared to Yuto will be = velocity of Riko - velocity of Yuto
= 0.35 - 0.25
= 0.10 miles per minute
Now we this relative velocity tells that Riko is moving and Yuto is in static position.
By the formula,
Average speed = ![\frac{Distance}{Time}](https://tex.z-dn.net/?f=%5Cfrac%7BDistance%7D%7BTime%7D)
0.10 = ![\frac{5.25}{t}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7Bt%7D)
t = ![\frac{5.25}{0.1}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7B0.1%7D)
t = 52.5 minutes
Now we know that Rico will catch Yuto in 52.5 minutes. Before this time he will be behind Yuto.
So duration of time in which Rico is behind Yuto will be 0 ≤ t ≤ 52.5
Here time can not be less than zero because time can not be with negative notation. It will always start from 0.