Answer:
5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)
6.) Frequency of R: 0.5
7.)Frequency of R: 0.5
8.)Frequency of R: 0.375
Explanation:
5.) If R and B code for the different forms of the same protein then they are only a few possible out comes
6.) First calculate the total alleles in population
allele R= 40
Allele B=40
total allele = R+B= 40+40
=80
Now to find allele R frequency is:
(Total R alleles) / (Total allele in pop)
40/80=
0.5
7.)Calculate the total alleles
Alleles from for R
RR= 10
R=10x 2= 20
Multiply the value by 2 because there are 2 R alleles present in
RB=20
R=20
Number doesn't change there is only 1 R allele
Total R=20+20
=40
Alleles For B
BB=10
B=10×2
=20
Same thing here, two B alleles together so multiple by 2
RB=20
B=20
Total B= 20+20
=40
Total alleles in pop add
40+40
=80
Frequency of R
Total of R/Total Alleles
=40/80
=0.5
8.)Repeat the same thing in 7 but use different numbers
RR=10
R=10x2
=20
RB=10
R=10
Total R= 20+10
=30
Answer:
<h2>Gold</h2>
Explanation:
Assume Gold trait =P ,
Purple= p,
Given:
Gold (P) is dominant over purple(p), so P is dominant over p.
If the bear is homozygous pp ( recessive) then bear will look purple,
If the bear is heterozygous Pp, then bear will look gold,
If the bear is homozygous DD( dominant), then the bear will look GOLD,
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