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Art [367]
2 years ago
12

Which statements accurately describe how to determine the y-intercept and the slope from the graph below?

Mathematics
1 answer:
nikdorinn [45]2 years ago
5 0

Its not because it dont go through the axis

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What is the answer to this question ?
Arisa [49]

Answer:

4

Step-by-step explanation:

h(7)= 7²-1= 49-1= 48

f(h(7))= 48/3 -12

= 16-12

= 4

7 0
3 years ago
Please help me out!!! :) 
Olin [163]

it would be > because the square root of 2 is more than 1.

8 0
3 years ago
Read 2 more answers
If f(x)= 3/x+2- square root x-3, complete the following statement: f(19)=
I am Lyosha [343]

f(7)≈1.6666                Please mark me as brainliest

round

f(7)=1.67

The domain of the function is the set of all the values of x that would allow the function to have real values. Since the radicand is x - 3, the value of x cannot be less than 3 because that would make the value of sqrt (x - 3) an imaginary number. Thus, the domain should be all numbers GREATER than or equal to 3.

8 0
3 years ago
Find the slope of the line.<br><br> A.) 3/2<br> B.) - 2/3<br> C.) - 3/4<br> D.) 4/3
Julli [10]
Option C is your answer. 

It's a negative sloping line which eliminates A and D. Then you just do the whole rise-over-run deal to get the 3/4 part. 
8 0
3 years ago
Points A, B and C lie on a circle, centre O.<br> Angle AOC = 142°.<br> Find the value of y.
aksik [14]

The value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

Let suppose that quadrilateral OABC is a parallelogram. Then, the following conditions must be fulfilled:

  1. \overline {OA} \cong \overline {BC}
  2. \overline{AB} \cong \overline{OC}
  3. \angle AOC \cong \angle ABC

In addition, if we have a rhombus we have the additional condition as A, B and C lie on the circle:

\overline{OA} \cong \overline {AB} \cong \overline {BC} \cong \overline{OC} (4)

If we know that \angle AOC = 142^{\circ}, then the value of \angle ABC = y = 142^{\circ}.

Based on all these finding, we conclude that the value of the angle y within the quadrilateral OABC inscribed the circle is 142°.

To learn more on parallelograms, we kindly invite to check this verified question: brainly.com/question/555469

5 0
2 years ago
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