I NEED HELP PLEASEEE ILL GIVE YOU MAX POINTS!!!

Hgunginwn v snvsdngsnanfanvsnsnshnsknbsjnjspejgnjdbhkjdkjf<br><br><br><br> whats sleep

Rasek [7]

Answer:

Step-by-step explanation:

when you lay down and close your eyes

7 0

3 years ago

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What is 25% off of $34.99?

lesya [120]

25% is a fourth of something so first round $34.99 to about $35 and just get one fouth of it which would be a little less than $9 but if you put it into the calculator it will tell you that it is about $8.75 (to calculate using the calculator you need to chane the percentage to a decimal and multiply it)

6 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So $n = 6, s = \frac{106}{\sqrt{6}} = 43.27$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 523}{43.27}$

$Z = -2.61$

$Z = -2.61$ has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0

3 years ago

Please help!! :(((((((

masha68 [24]

The answers would be 11, if you plug it in it would be 5(11)-7=48

3 0

3 years ago

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The measures of the angles of a triangle are ∠A = (2x)°, ∠B = (x+14)°, ∠C = (x−38)° Determine the value of x. Determine A B and

nexus9112 [7]

Answer:

Step-by-step explanation:

Measures of angles are,

m∠A = (2x)°

m∠B = (x + 14)°

m∠C = (x - 38)°

By triangle sum theorem,

m∠A + m∠B + m∠C = 180°

2x + (x + 14) + (x - 38) = 180

(2x + x + x) + (14 - 38) = 180

4x - 24 = 180

4x = 204

x = 51

m∠A = 2(51)° = 102°

m∠B = (51 + 14)° = 65°

m∠C = (51 - 38)° = 13°

4 0

2 years ago