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emmainna [20.7K]
3 years ago
5

I NEED HELP PLEASEEE ILL GIVE YOU MAX POINTS!!!

Mathematics
1 answer:
Lorico [155]3 years ago
3 0
1. 0.54 or 27/50
2. 148.24
3. 0.567735
4. 1.01129
5. 18101.26086
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In 2010 the population of alaska was about 710200 what is this number written in word form
Svetradugi [14.3K]
Seven hundred and ten thousand two hundred
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3 years ago
PLS I NEED HELP GUYS IM DESPERATE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
goldenfox [79]

Answer:

3,4,5 because they only need one dice to be rolled while the rest need to dice to land perfectly

Step-by-step explanation:

4 0
4 years ago
The Federal Pell Grant Program gives grants to low-income undergraduate students. According to the National Postsecondary Studen
Gekata [30.6K]

Answer: the t-test statistic is - 1.77

Step-by-step explanation:

For the null hypothesis,

H 0: μ = 2600

For the alternative hypothesis,

H a: μ ≠ 2600

This is a two tailed test

Since no population standard deviation is given, the distribution is a student's t.

Since n = 50,

Degrees of freedom, df = n - 1 = 50 - 1 = 49

t = (x - µ)/(s/√n)

Where

x = sample mean = $2450

µ = population mean = $2600

s = samples standard deviation = $600

Therefore,

t = (2450 - 2600)/(600/√50) = - 1.77

3 0
3 years ago
HELLLLPPPPPPPPPPPPPPPPPPPPPPPPPPP
Natali5045456 [20]

Answer:

3/1

Step-by-step explanation:

5 0
3 years ago
How many business students must be randomly selected to estimate the mean monthly earnings of business students at one college?
marysya [2.9K]

Answer:

Approximately 63 business students must be randomly selected to estimate the mean monthly earnings of business students at one college

Step-by-step explanation:

confidence interval = 95%

Standard deviation (\sigma )  = 569

\alpha = 1 - 0.95 = .05

Z_{\frac{\alpha }{2}}  = Z_{\frac{.05 }{2}}  = 1.96

We want 95% confidence that the sample mean is within $140 of the population mean

margin of error ( E ) =140

let n be the sample size

margin of error ( E ) = Z_{\frac{\alpha }{2}}\frac{\sigma }{\sqrt{n}}

      squarring both side

E^{2} = 1.96^{2}\times\frac{\sigma ^{2}}{n}

n = \frac{1.96^{2}}{140^{2}}\times 569^{2}

n = 63.45

n =63 approximately

8 0
4 years ago
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