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2 years ago

Help I think the answer is either A or D.

Chemistry

2 answers:

devlian [24]2 years ago

4 0

Answer:

Explanation:

Miss Girl. Snow isn't in Nevada-

Setler79 [48]2 years ago

4 0

It is a snowpacks !!!!

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What is the pH of .0003 M of NaOH

s344n2d4d5 [400]

We are given that the concentration of NaOH is 0.0003 M and are asked to calculate the pH

We know that NaOH dissociates by the following reaction:

NaOH → Na⁺ + OH⁻

Which means that one mole of NaOH produces one mole of OH⁻ ion, which is what we care about since the pH is affected only by the concentration of H⁺ and OH⁻ ions

Now that we know that one mole of NaOH produces one mole of OH⁻, 0.0003M NaOH will produce 0.0003M OH⁻

Concentration of OH⁻ (also written as [OH⁻]) = 3 * 10⁻⁴

pOH of the solution:

pOH = -log[OH⁻] = -log(3 * 10⁻⁴)

pOH = -0.477 + 4

pOH = 3.523

pH of the solution:

We know that the sum of pH and pOH of a solution is 14

pH + pOH = 14

pH + 3.523 = 14 [subtracting 3.523 from both sides]

pH = 10.477

8 0

3 years ago

Iupac names of the following

Nadusha1986 [10]

It’s blurry.... try again

6 0

2 years ago

A weather balloon is inflated to a volume of 27.9L at a pressure of 732mmHg and a temperature of 30.1?C. The balloon rises in th

masya89 [10]

Answer:

45.4 L

Explanation:

Using Ideal gas equation for same mole of gas as

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

Given ,

V₁ = 27.9 L

V₂ = ?

P₁ = 732 mmHg

P₂ = 385 mmHg

T₁ = 30.1 ºC

T₂ = -13.6 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (30.1 + 273.15) K = 303.25 K

T₂ = (-13.6 + 273.15) K = 259.55 K

Using above equation as:

$\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}$

$\frac{{732}\times {27.9}}{303.25}=\frac{{385}\times {V_2}}{259.55}$

$\frac{385V_2}{259.55}=\frac{20422.8}{303.25}$

$148225V_2=6729708.26018$

Solving for V₂ , we get:

V₂ = 45.4 L

7 0

4 years ago

What type of bond results from the electrostatic attraction between positive and negative atoms?

Juliette [100K]

It is called a ionic bond

4 0

3 years ago

A mixture of water and acetone at 756 mm boils at 70.0°C. The vapor pressure of acetone is

Tatiana [17]

Given :

A mixture of water and acetone at 756 mm boils at 70.0°C.

The vapor pressure of acetone is 1.54 atm at 70.0°C, while the vapor pressure of water is 0.312 atm at the same temperature.

To Find :

The percentage composition of the mixture.

Solution :

By Raoult's law :

$P=x_{acetone}P^o_{acetone}+x_{water}P^o_{water}\\\\x_{acetone}1.58+x_{water}0.312=\dfrac{756}{760}=0.995\ atm\\\\1.58x_a+0.312x_w=0.995$ ......( 1 )

Also , $x_a+x_b=1$ ......( 2 )

Solving equation 1 and 2 , we get :

$x_a=0.54\ and \ x_w=0.46$ .

Mass of acetone ,

$m_a=x_a\times MM_a\\\\m_a=0.54\times 58\\\\m_a=31.32\ g$

Mass of water ,

$m_w=x_w\times MM_w\\\\m_w=0.46\times 18\\\\m_a=8.28\ g$

$\%water =\dfrac{8.28}{8.28+31.32}\times 100\\\\\%water =20.9\%\\\\\%acetone =79.1\%$

Hence , this is the required solution.

6 0

3 years ago