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1 year ago

Help I think the answer is either A or D.

Chemistry

2 answers:

devlian [24]1 year ago

4 0

Answer:

Explanation:

Miss Girl. Snow isn't in Nevada-

Setler79 [48]1 year ago

4 0

It is a snowpacks !!!!

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A 4Kg rock is rolling 10m/s find it’s kinetic energy

Lubov Fominskaja [6]

KE=.5mv^2
M=mass
v=velocity
.5(4)(100)=200
That should be the answer.

5 0

2 years ago

I need information about <br>"forming colloid"<br>THANK YOU!

notka56 [123]

Answer:

Condensation methods from colloidal particles by aggregation of molecules or ions. Examples of colloids are really in common in evryday life, eg. Mayonnaise, butter, milk, gelatin, paper etc..

Every colloid consists of two parts :colloidal particles and the dispersing medium.

3 0

2 years ago

The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an

ser-zykov [4K]

Answer:

$24540\frac{mg}{m^3}$

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

$\frac{3L\ CO}{L\ gas}$

By using the ideal gas equation we compute the density of CO:

$\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L$

Then we apply the conversion factors as follows:

$=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}$

Regards.

4 0

3 years ago

While conducting a lab experiment, Ali calculated that 1.20 E6 Joules of heat were needed to melt 18.5 kilograms of an unknown s

nordsb [41]

Answer:

Latent heat of fusion of the substance is $6.49\times 10^{4}J/kg$

Explanation:

Latent heat of fusion denotes amount of energy (heat) per unit mass required to melt a solid material at constant temperature and pressure i.e. at it's melting point

Here amount of heat required = $1.20\times 10^{6}J$

Mass of unknown substance being melted = 18.5 kg

So, latent heat of fusion of the substance = (required heat energy to melt)/(mass of the unknown substance) = $\frac{1.20\times 10^{6}}{18.5}J/kg=6.49\times 10^{4}J/kg$

So, latent heat of fusion of the substance is $6.49\times 10^{4}J/kg$

7 0

2 years ago

When a 4.2 gram sample of mercury (Il) oxide, HgO is decomposed into its elements by •

Usimov [2.4K]

Hg = (3.2 : 4.2) x 100% = 76.19%

O = (1 : 4.2) x 100% = 23.81%

7 0

2 years ago