
B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark.
Answer:
There is no attachment
however, u could remove the object
An Erlenmeyer flask is also termed as conical flask and titration flask. Invented in the year 1860. It is made up of glass and plastic. Inventer - Emil Erlenmeyer
Weight of empty erlenmeyel flask = 79.83 g
Weight after addition of water = 89.82 g
Weight of water = 89.82 - 79.83 = 9.99 g
Density of water at 22 deg celcius = 0.99777
Density = mass / volume
Volume = mass / density
= 9.99 g / 0.99777 g/ ml
= 10.01 ml
Calculated volume of water that the student measured is 10.01 ml.
To know more about Erlenmeyer flask here :
brainly.com/question/10261429?referrer=searchResults
#SPJ4
Answer:
0.0922 M
Explanation:
The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.
The reaction that takes place is:
- HClO₄ + NaOH → NaClO₄ + H₂O
First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:
- 0.624 M * 13.0 mL = 8.11 mmol HClO₄
Then we <u>calculate how many NaOH moles were added</u>:
- 0.258 M * 15.0 mL = 3.87 mmol NaOH
Now we calculate how many HClO₄ remained after the reaction:
- 8.11 - 3.87 = 4.24 mmol HClO₄
As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺
Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:
- Final volume = 31.0 mL + 15.0 mL = 46.0 mL
- 4.24 mmol / 46.0 mL = 0.0922 M