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dezoksy [38]
3 years ago
15

Blood with a lot of oxygen in it is ___________red a bright b dark

Chemistry
1 answer:
o-na [289]3 years ago
5 0

Answer:

bright red.

Explanation:

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How would you prepare 3.5 L of a 0.9M solution of KCl?
PolarNik [594]
V=3,5L\\
Cm=0,9M\\
M_{KCl}=74\frac{g}{mol}\\\\
C_{m}=\frac{n}{V}\\\\
n=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV} \ \ \ \Rightarrow  \ \ \ m=C_{m}MV\\\\
m=0,9\grac{mol}{L}*74\frac{g}{mol}*3,5L=233,1g

B. Add 233 g of KCl to a 3.5 L container; then add enough water to dissolve the KCl and fill the container to the 3.5 L mark. 
4 0
3 years ago
Which of the following is a way that the pressure of an object can be decreased?
GrogVix [38]

Answer:

There is no attachment

however, u could remove the object

8 0
3 years ago
Read 2 more answers
Please help y’all I don’t understand
DedPeter [7]

Answer:

the last one

Explanation:

6 0
3 years ago
A student in chm 11500 lab measured the mass of a 250-ml erlenmeyer flask and recorded it as 79. 83 g. She added 10. 00 ml of de
umka2103 [35]

An Erlenmeyer flask is also termed as conical flask and titration flask. Invented in the year 1860. It is made up of glass and plastic. Inventer - Emil Erlenmeyer

Weight of empty erlenmeyel flask = 79.83 g

Weight after addition of water = 89.82 g

Weight of water = 89.82 - 79.83 = 9.99 g

Density of water at 22 deg celcius = 0.99777

Density = mass / volume

Volume = mass / density

= 9.99 g / 0.99777 g/ ml

= 10.01 ml

Calculated volume of water that the student measured is 10.01 ml.

To know more about Erlenmeyer flask here :

brainly.com/question/10261429?referrer=searchResults

#SPJ4

7 0
11 months ago
A 31.0 mL sample of 0.624M perchloric acid is titrated with a 0.258M sodium hydroxide solution.
levacccp [35]

Answer:

0.0922 M

Explanation:

The problem first states that the titration is made using NaOH, and later asks about the addition of KOH. I'm going to assume NaOH was used throughout the whole problem. The result does not change if it was KOH instead.

The reaction that takes place is:

  • HClO₄ + NaOH → NaClO₄ + H₂O

First we <u>calculate how many HClO₄ moles are there in the sample</u>, using the <em>given molarity and volume</em>:

  • 0.624 M * 13.0 mL = 8.11 mmol HClO₄

Then we <u>calculate how many NaOH moles were added</u>:

  • 0.258 M * 15.0 mL = 3.87 mmol NaOH

Now we calculate how many HClO₄ remained after the reaction:

  • 8.11 - 3.87 = 4.24 mmol HClO₄

As <em>HClO₄ is a strong acid</em>, 4.24 mmol HClO₄ = 4.24 mmol H⁺

Finally we <u>calculate the molarity of H⁺</u>, using the<em> calculated number of moles and final volume</em>:

  • Final volume = 31.0 mL + 15.0 mL = 46.0 mL
  • 4.24 mmol / 46.0 mL = 0.0922 M
5 0
3 years ago
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