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ale4655 [162]
3 years ago
12

Consider the reaction H2(g) + I2(g) Double headed arrow. 2HI(g). What is the reaction quotient, Q, for this system when [H2] = 0

.100 M, [I2] = 0.200 M, and [HI] = 3.50 M?
87.5
175
350
613
Chemistry
2 answers:
Alexeev081 [22]3 years ago
8 0

Answer:

613

Explanation:

trust me

irakobra [83]3 years ago
5 0

Answer:

163

Explanation:

hope it helps!

please mark as the brainliest if it is correct!

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Products of MnO + CL2
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If the equation is complete the products would be manganese chloride and oxygen gas would be given off.

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If you take a part time job while you are still in school what might your opportunity scost be
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Elements ending in the electron configurations ns^1 are highly reactive metals . What family does these elements belong to ?
myrzilka [38]

Answer:

<h3>A . Alkali metals</h3>

Explanation:

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6 0
3 years ago
Solutions can only be separated by using distillation not filtration. Why can't a solution be filtered? Explain using the terms
garri49 [273]
<h2>Solutions</h2>

Explanation:

  • Solutions are formed when a solute gets dissolved in a solvent. The solid that gets dissolved is called solute whereas the liquid in which the solid gets dissolved is called the solvent. On dissolving,  the particles of the solute  gets incorporated between the inter-particle space of the solvent. This means that there is no significant difference between the particle size of solute and solvent. However the boiling points of solutions can differ significantly. This is the reason, the solutions cannot be separated by the method of filtration but by the method of distillation.
5 0
3 years ago
What volume of 24% trichloroacetic acid (tca) is needed to prepare eight 3 ounce bottles of 10% tca solution?
Sever21 [200]

Answer:

295.7 mL of 24% trichloroacetic acid (tca) is needed .

Explanation:

Let the volume of 24% trichloroacetic acid solution be x

Volume of required 10% trichloroacetic acid solution =8 bottles of 3 ounces

= 24 ounces = 709.68 mL

(1 ounces =  29.57 mL)

Amount of trichloroacetic acid in 24% solution of x volume of solution will be equal to amount of trichloroacetic acid in 10% solution of volume 709.68 mL.

x\times \frac{24}{100}=709.68 mL\times \frac{10}{100}

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295.7 mL of 24% trichloroacetic acid (tca) is needed .

6 0
3 years ago
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