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romanna [79]
3 years ago
14

Create a list of 5 potential jobs that students of psychology can obtain.

Chemistry
1 answer:
Alex3 years ago
4 0

Answer:

1. guidance counselor

2.mental health worker

3.social worker

4.human resources worker

5. substance abuse counselor

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Write an interesting good presentation of acid and base​
aleksley [76]
<h2>★<u>Acid</u></h2>

  • these are sour in taste
  • corrosive in nature
  • the turn blue litmus to red when litmus paper is dipped into it
  • we also eat acids like citric acid in our daily life
<h2>★<u>Base</u></h2>

  • bitter in taste
  • soapy to touch
  • turn red litmus to Blue
  • we use bases like milk of magnesia and antacid in our daily life

Hope it helps u

5 0
3 years ago
A change of matter is a physical change <br>True or False​
kodGreya [7K]

Answer:

true

Explanation:

hope it helps

8 0
3 years ago
Read 2 more answers
The formula for the table salt is NaCl. Is table salt ionic or covalent? Explain.
mel-nik [20]

Answer:

ionic

it is a mixture of a nonmetal and a metal which is what makes ionic compounds

covalent is a nonmetal and nonmetal

Explanation:

6 0
3 years ago
An unspecified ratio of nitrogen gas and hydrogen gas are mixed in a container and then react to form ammonia. the initial mole
Tanzania [10]
<span>The initial mole fraction of the hydrogen gas is the same value as the nitrogen gas due to the fact neither material consumes the other. Because of this equal ratios where mixed initially, with the outcome in volume being the same.</span>
5 0
3 years ago
It takes 330 joules of energy to raise the temperature of 24.6 gbenzene from 21 degrees Celsius to 28.7 degrees Celsius at const
lilavasa [31]

Given :

Energy , E = 330 J .

Initial temperature , T_i=21^oC .

Final temperature , T_f=24.6^oC .

Mass of benzene , m = 24.6 g .

To Find :

The molar hear capacity of benzene at constant pressure .

Solution :

Molecular mass of benzene , M = 78 g/mol .

Number of moles of benzene :

n=\dfrac{24.6}{78} \ mol\\\\n=0.32 \ mol

Energy required is given by :

q=nC_p\Delta T\\\\330=0.32\times C_p\times (28.7-21)\\\\C_p=\dfrac{330}{0.32\times 7.7}\ J\ mol^{-1}^oC^{-1} \\\\C_p=133.9\ J\ mol^{-1}^oC^{-1}

Hence , this is the required solution .

8 0
3 years ago
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