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3 years ago

Create a list of 5 potential jobs that students of psychology can obtain.

Chemistry

1 answer:

Alex3 years ago

4 0

Answer:

1. guidance counselor

2.mental health worker

3.social worker

4.human resources worker

5. substance abuse counselor

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Consider a mixture of NaCl and NaNO3 that is 31.8% Na by mass. Calculate the percentage by mass of NaCl in the mixture.

lutik1710 [3]

Answer: The percentage by mass of NaCl in the mixture is 38.5 %

Explanation:

To calculate the mass percentage of element in compound, we use the equation:

$\text{Mass percent of element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100$ .......(1)

For NaCl:

Mass of sodium element = 23 g

Mass of NaCl = 58.5 g

Putting values in equation 1, we get:

$\text{Mass percent of sodium element}=\frac{23g}{58.5g}\times 100=39.32\%$

Mass fraction of sodium metal in NaCl = 0.3932

For $NaNO_3$ :

Mass of sodium element = 23 g

Mass of $NaNO_3$ = 85 g

Putting values in equation 1, we get:

$\text{Mass percent of sodium element}=\frac{23g}{85g}\times 100=27.1\%$

Mass fraction of sodium metal in sodium nitrate = 0.271

Let us assume the mass fraction of NaCl in the mixture is 'x'

So, the mass fraction of $NaNO_3$ in the mixture will be '(1-x)'

We are given:

Percent by mass of Na in the mixture = 31.8 %

Mass fraction of Na in the mixture = 0.318

Evaluating the mass fraction of NaCl in the mixture:

$[(x\times 0.3932)+((1-x)\times 0.271)]=0.318$

x = 0.385

Percent by mass of NaCl in the mixture will be = $(0.385\times 100)=38.5\%$

Hence, the percentage by mass of NaCl in the mixture is 38.5 %

4 0

3 years ago

I NEED HELP ASAPPPPPPPPPPPPPPPP

RoseWind [281]

Answer:

i wold think it is C

Explanation:

8 0

3 years ago

Read 2 more answers

How many moles of water are produced from 19.2 g of B2H6

lbvjy [14]

The Balanced chemical equation of reaction of Borane with oxygen is as follow,
B₂H₆ + 3O₂ -----> 2HBO₂ + 2H₂O
According to this equation 27.66 g (1 mole) of B₂H₆ reacts with oxygen to produce 36 g (2 moles) of water.
The amount of water produced when 19.2 g of B₂H₆ reacted is calculated as follow,
$\frac{27.66 g B2H6 produced}{19.2 g of B2H6 will produce}$ = $\frac{36 g of H2O}{x g of water}$
Solving for x,
x = (36 g of H₂O ₓ 19.2 g of H₂B₆) / 27.66 g of B₂H₆

x = 24.98 g of H₂O

Result:
24.98 g of water is produced when 19.2 g of B₂H₆ is reacted with excess of oxygen.

5 0

3 years ago

Which products result from the process of photosynthesis? Check all that apply.

SashulF [63]

The answer is carbon dioxide

3 0

4 years ago

Read 2 more answers

A sample of water vapor at 105 C is cooled to 95 C.

kakasveta [241]

I beleive its A but not very sure though. If im wrong sorry. But if im right I hope it helps (:

7 0

3 years ago