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Ratling [72]
3 years ago
15

Hard time with these type of problems, need help

Mathematics
1 answer:
amid [387]3 years ago
4 0
Not sure I have had idea of what it is but I don’t wanna give u the wrong answer
You might be interested in
At the start of the experiment substance is measured to be 70°C, and by the end of the experiment its temperature is measured as
11Alexandr11 [23.1K]

9514 1404 393

Answer:

  -130 °C

Step-by-step explanation:

The change is found by subtracting the start temperature from the finish temperature. It is ....

  -60 °C - 70 °C = -130 °C

3 0
3 years ago
Look at the figure, . Find the values of ​x and y. x = 5, y = 7 x = 6, y = 8 x = 6, y = 9 x = 7, y = 10
Colt1911 [192]

Answer:

x = 6, y = 9

Step-by-step explanation:

One of the properties of a parallelogram is

The diagonals bisect each other, hence

2x = y + 3 → (1)

2y = 3x → (2)

Rearrange (1) in terms of y by subtracting 3 from both sides

y = 2x - 3 → (3)

Substitute y = 2x - 3 into (2)

2(2x - 3) = 3x ← distribute left side

4x - 6 = 3x ( add 6 to both sides )

4x = 3x + 6 ( subtract 3x from both sides )

x = 6

Substitute x = 6 into (3) for value of y

y = (2 × 6) - 3 = 12 - 3 = 9

Hence x = 6 and y = 9

5 0
4 years ago
Mathematically verify the outlier(s) in the data set using the 1.5 rule.
statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

Q_1=\dfrac{11+13}{2}

Q_1=\dfrac{24}{2}

Q_1=12

And

Q_3=\dfrac{16+16}{2}

Q_3=\dfrac{32}{2}

Q_3=16

The interquartile range is:

IQR=Q_3-Q_1

IQR=16-12

IQR=4

The data values lies outside the interval [Q_1-1.5IQR,Q_3+1.5IQR] are known as outliers.

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]

[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]

[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0
3 years ago
16+1008=<br><br> 56+20<br><br> please help me
kicyunya [14]
16+1008 = 1024

56+20=76
7 0
2 years ago
Read 2 more answers
Help me please thank you.
Alexus [3.1K]
J would have to say that the answer is d. im sorry if im wrong.
4 0
3 years ago
Read 2 more answers
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