Define i as a unit vector in the eastern direction.
Define j as a unit vector in the northern direction.
Part I
Because the wind is blowing west, its velocity vector is
-23i mph or as (-23, 0) mph
Because the plane is traveling north, its velocity vector is
200j mph or as (0, 200) mph
Part II
The actual velocity of the plane is the vector sum of the plane and wind velocities.
That is,
200j - 23i or (-23, 200) mph
Part III
The ground speed of the plane is the magnitude of its vector.
The ground speed is
√[200² + (-23)²] = 201.32 mph
The ground speed of the plane is 201.3 mph (nearest tenth)
Not:
The direction of the plane is
tan⁻¹ 23/200 = 6.56° west of north.
Answer:
(10^2)*2, 10*3, 10/2
Step-by-step explanation:
Thats my best guess to your very vague question
Answer:
area of triangle= 1/2*h*b
= 1/2*6*16
=3*16
= 48 yd²
This is your answer. If I'm right so,
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Given cos theta is equal to - 4/ 7 then we can conclude that theta is in the second and third quadrants. In this case, the other leg is equal to square root of (7^2 - 4^2 ) equal to square root of 33. In this case, sin theta can be equal to +- square root of 33 / 7 and tan theta is equal to +-square root of 33 / 4.
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